The number of sugar cubes in the box is 180
<h3>How to determine the number of sugar cubes?</h3>
The given parameters are:
- Layers = 5
- Pieces = 2 or 3
- Cups of tea = 61 and 88
Multiply 61 and 88 by 2 and 3
61 * 2 = 122
61 * 3 = 183
88 * 2 = 176
88 * 3 = 264
The number of sugar cubes cannot be 122 and 264, because they are out of the range
So, we have:
183 and 176
There are 5 layers.
This means that the number of sugar cubes is divisible by 5.
The only number between 176 and 183 that is divisible by 5 is 180
Hence, the number of sugar cubes is 180
Read more about sequence at:
brainly.com/question/21961097
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Answer:
A fish processing company in Charlotteville processes three types of products: Type A, Type B, and Type C. Its operations involve three basic activities: cleaning, cutting and packaging.
Step-by-step explanation:
Answer:
The correct answer is$5.50 for 5
Step-by-step explanation:
5.50/5=1.1
<h2>
Hello!</h2>
The answers are:
A.
and ![\frac{10}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B10%7D%7B12%7D)
D.
and ![1\frac{5}{7}](https://tex.z-dn.net/?f=1%5Cfrac%7B5%7D%7B7%7D)
<h2>
Why?</h2>
To find which of the following pairs of numbers contains like fractions, we must remember that like fractions are the fractions that share the same denominator.
We are given two fractions that are like fractions. Those fractions are:
Option A.
and ![\frac{10}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B10%7D%7B12%7D)
We have that:
![\frac{10}{12}=\frac{5}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B10%7D%7B12%7D%3D%5Cfrac%7B5%7D%7B6%7D)
So, we have that the pairs of numbers
and
![\frac{5}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B6%7D)
Share the same denominator, which is equal to 6, so, the pairs of numbers contains like fractions.
Option D.
and ![1\frac{5}{7}](https://tex.z-dn.net/?f=1%5Cfrac%7B5%7D%7B7%7D)
We have that:
![1\frac{5}{7}=1+\frac{5}{7}=\frac{7+5}{7}=\frac{12}{7}](https://tex.z-dn.net/?f=1%5Cfrac%7B5%7D%7B7%7D%3D1%2B%5Cfrac%7B5%7D%7B7%7D%3D%5Cfrac%7B7%2B5%7D%7B7%7D%3D%5Cfrac%7B12%7D%7B7%7D)
So, we have that the pair of numbers
and
![\frac{12}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B12%7D%7B7%7D)
Share the same denominator, which is equal to 7, so, the pairs of numbers constains like fractions.
Also, we have that the other given options are not like fractions since both pairs of numbers do not share the same denominator.
The other options are:
![\frac{3}{2},\frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D%2C%5Cfrac%7B2%7D%7B3%7D)
and
![3\frac{1}{2},4\frac{4}{4}](https://tex.z-dn.net/?f=3%5Cfrac%7B1%7D%7B2%7D%2C4%5Cfrac%7B4%7D%7B4%7D)
We can see that both pairs of numbers do not share the same denominator so, they do not contain like fractions.
Hence, the answers are:
A.
and ![\frac{10}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B10%7D%7B12%7D)
D.
and ![1\frac{5}{7}](https://tex.z-dn.net/?f=1%5Cfrac%7B5%7D%7B7%7D)
Have a nice day!