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3 years ago

Help me answer this chemistry question. thank you!

Chemistry

1 answer:

Vladimir79 [104]3 years ago

8 0

Answer:

Chlorine and bromine

Explanation:

I think thats the answer in your question

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Tarnish on copper is the compound CuO. A tarnished copper plate is placed in an aluminum pan of boiling water. When enough salt

oksian1 [2.3K]

Answer:

The standard cell potential is 2.00 V

Explanation:

Step 1: Data given

Cu is cathode because of higher EP

Al3++3e−→Al E∘=−1.66 V anode

Cu2++2e−→Cu E∘=0.340 V cathode

Step 2: Balance both equations

2*(Al → Al3+-3e−) E∘=1.66 V

3*(Cu2++2e−→Cu) E∘=0.340 V

Step 3: The netto equation

2 Al + 3Cu2+ +6e- → 2Al3+ + 3Cu -6e-

2 Al + 3Cu2+ → 2Al3+ + 3Cu

Step 4: Calculate the standard cell potential

E∘cell = E∘cathode - E∘anode

E∘cell = E∘ Cu2+/Cu - E∘ Al3+/Al

E∘cell =0.340 V - (-1.66) = 2.00 V

The standard cell potential is 2.00 V

4 0

3 years ago

Which of the following is the correct equation for the reaction below?

fenix001 [56]

Answer:

Option C.

2 Mg (s) + O₂(g) → 2MgO (s)

Explanation:

Two moles of magnesium solid react with one mol of oxygen gas to

form two moles of magnesium-oxide solid

2 Mg (s) + O₂(g) → 2MgO (s)

That's the reaction for the magnessium oxide's formation.

Be careful cause we do not say molecules, they are moles.

The stoichiometry indicates the number of moles that react and the moles which are produced.

It is a redox reaction, because the magnessium is oxidized and the oxygen is reduced. Both elements, changed the oxidation states.

4 0

3 years ago

Read 2 more answers

What element has the atomic number 11

andreev551 [17]

Neon I think. Go to the periodic table and see which one is the 11th

5 0

3 years ago

Read 2 more answers

For which of the following aqueous solutions would one expect to have the largest van’t Hoff factor (i)? a. 0.050 m NaCl b. 0.50

ira [324]

Answer:

The van't hoff factor of 0.500m K₂SO₄ will be highest.

Explanation:

Van't Hoff factor was introduced for better understanding of colligative property of a solution.

By definition it is the ratio of actual number of particles or ions or associated molecules formed when a solute is dissolved to the number of particles expected from the mass dissolved.

a) For NaCl the van't Hoff factor is 2

b) For K₂SO₄ the van't Hoff factor is 3 [it will dissociate to give three ions one sulfate ion and two potassium ions]

Out of 0.500m and 0.050m K₂SO₄, the van't hoff factor of 0.500m K₂SO₄ will be more.

c) The van't Hoff factor for glucose is one as it is a non electrolyte and will not dissociate.

7 0

3 years ago

If 10.0 moles of sulfur dioxide react with excess chlorine gas, what is the theoretical yield (in grams) of CI2O produced?

xz_007 [3.2K]

Answer:

869 g Cl₂O

Explanation:

To find the theoretical yield of Cl₂O, you need to (1) convert moles SO₂ to moles Cl₂O (via mole-to-mole ratio from reaction coefficients) and then (2) convert moles Cl₂O to grams Cl₂O (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs to reflect the sig figs of the given amount (10.0 moles).

1 SO₂ (g) + 2 Cl₂ (g) ----> 1 SOCl₂ (g) + 1 Cl₂O (g)

Molar Mass (Cl₂O): 2(35.453 g/mol) + 15.998 g/mol

Molar Mass (Cl₂O): 86.904 g/mol

10.0 moles SO₂ 1 mole Cl₂O 86.904 g
------------------------ x ---------------------- x ------------------ = 869 g Cl₂O
1 mole SO₂ 1 mole

6 0

2 years ago