Answer:
Explanation:
This is a direct application of the equation for ideal gases.
Where:
Solving for n:
Substituting:
Answer : 0.0392 grams of Zn metal would be required to completely reduced the vanadium.
Explanation :
Let us rewrite the given equations again.
On adding above equations, we get the following combined equation.
We have 12.1 mL of 0.033 M solution of VO₂⁺.
Let us find the moles of VO₂⁺ from this information.
From the combined equation, we can see that the mole ratio of VO₂⁺ to Zn is 2:3.
Let us use this as a conversion factor to find the moles of Zn.
Let us convert the moles of Zn to grams of Zn using molar mass of Zn.
Molar mass of Zn is 65.38 g/mol.
We need 0.0392 grams of Zn metal to completely reduce vanadium.
Answer:
4.6 mol Si
General Formulas and Concepts:
<u>Atomic Structure</u>
<u>Stoichiometry</u>
Explanation:
<u>Step 1: Define</u>
[Given] 2.8 × 10²⁴ atoms Si
[Solve] moles Si
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
4.64962 mol Si ≈ 4.6 mol Si