Answer:
Mass of CO₂ produced = 5.72 g
Explanation:
Given data:
Mass of methane = 2.34 g
Mass of oxygen = 8.32 g
Mass of CO₂ produced = ?
Solution:
Chemical equation:
CH₄ + 2O₂ → CO₂ + 2H₂O
Number of moles of methane:
Number of moles = mass/molar mass
Number of moles = 2.34 g/ 16 g/mol
Number of moles = 0.146 mol
Number of moles of oxygen:
Number of moles = mass/molar mass
Number of moles = 8.32 g/ 32 g/mol
Number of moles = 0.26 mol
Now we will compare the moles of carbon dioxide with oxygen and methane.
CH₄ : CO₂
1 : 1
0.146 : 0.146
O₂ : CO₂
2 : 1
0.26 : 1/2×0.26 = 0.13 mol
Less number of moles of CO₂ are produced by oxygen thus oxygen will react as limiting reactant.
Mass of CO₂:
Mass = number of moles × molar mass
Mass = 0.13 mol × 44 g/mol
Mass = 5.72 g
The question is incomplete. Here is the complete question.
A nitric acid solution containing 71.0% HNO₃ (by mass) has a density of 1.42g/mL. How many moles of HNO₃ are present in 1.98L of this solution?
a. 62.8 mol
b. 31.7 mol
c. 22.3 mol
d. 3.16 x 10⁻² mol
e. none of these
Answer: b. 31.7 mol
Explanation: The solution has density of 1.42g/mL. So, in 1980 mL of solution:
m = d.V
m = 1.42(1980)
m = 2811.6 g
There are 2811.6 grams of solute.
Nitric acid in this solution is 71% by mass, which means
m = 2811.6(0.71)
m = 1996.236 g
In this solution, mass of nitric acid is 1996.236 grams.
Molar mass of HNO₃ is M = 63.01g/mol.
Then:
n = 31.68 moles
In 1.98L of a nitric acid solution, there are 31.7 moles of HNO₃.
That's a compound
The Cu stands for Copper, and the O stands for oxygen
In order for plants to go through photosynthesis, they must use <span>B. visible light.</span>
The mass percentage of the copper (Cu) in the compound CuSO₄ is 39.81%.
<h3>What is the mass percentage?</h3>
The percentage of an element in a compound can be determined as the number of parts by mass of that element present in 100 parts by mass of the given compound.
First, calculate the molecular mass of the given compound by the addition of the atomic masses of all the present elements in the molecular formula. Then, the percentage of the elements can be determined by dividing the total mass of the element by the molar mass of the compound multiplied by 100.
Given, the atomic mass of copper, sulfur, and oxygen is 63.55 g, 32.07 g, and 16.0g respectively.
The molecular mass of CuSO₄ = 63.55 + 32.07 + 4(16.0) = 159.62 g.
The mass percentage of the Sulphur = (63.55/159.62) × 100 = 39.81%.
Therefore, the mass percentage of Copper is equal to 39To learn.
Learn more about the mass percentage, visit here:
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