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nika2105 [10]
3 years ago
6

In order for plants to go through photosynthesis, they must use

Chemistry
1 answer:
Alex_Xolod [135]3 years ago
8 0
In order for plants to go through photosynthesis, they must use <span>B. visible light.</span>
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Please Help Why is laboratory safety important? Describe a scenario illustrating your reason(s).
Virty [35]
So that you can learn while being safe. Wearing goggles, for eye protection when dealing with chemicals
3 0
3 years ago
A piece of wood with a density of 0.85 g/cm^3 has a mass of 25 g. what is the volume of the wood?
Karolina [17]
Density = m/v  therefore    v = m/d     v = 25/0.85    v = 29.4117... cm^3 ( = 2.94 * 10^-5 m^3
5 0
3 years ago
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If I started with 42.00 L of oxygen (O2) gas, how many grams is that?
belka [17]

Answer:

42 liters of oxygen (liquid) weighs 47900 grams.

Explanation:

5 0
2 years ago
If 12.5 grams of strontium hydroxide is reacted with 150 mL of 3.5 M carbonic acid, identify the limiting reactant.
vesna_86 [32]

Answer:

Sr(OH)2

Explanation:

We'll begin by calculating the number of mole of carbonic acid in 150mL of 3.5 M carbonic acid solution. This is illustrated below:

Molarity = 3.5M

Volume = 150mL = 150/1000 = 0.15L

Mole of carbonic acid, H2CO3 =..?

Mole = Molarity x Volume

Mole of carbonic acid, H2CO3 = 3.5 x 0.15 = 0.525 mole.

Next, we shall convert 0.525 mole of carbonic acid, H2CO3 to grams.

Mole of H2CO3 = 0.525 mole

Molar mass of H2CO3 = (2x1) + 12 + (16x3) = 62g/mol.

Mass of H2CO3 =..?

Mass = mole x molar mass

Mass of H2CO3 = 0.525 x 62 = 32.55g

Next, we shall write the balanced equation for the reaction. This is given below:

Sr(OH)2 + H2CO3 → SrCO3 + 2H2O

Next, we shall determine the mass of Sr(OH)2 and H2CO3 that reacted from the balanced equation. This is illustrated below:

Molar mass of Sr(OH)2 = 88 + 2(16 + 1) = 88 + 2(17) = 122g/mol

Mass of Sr(OH)2 from the balanced equation = 1 x 122 = 122g

Molar mass of H2CO3 = (2x1) + 12 + (16x3) = 62g/mol.

Mass of H2CO3 from the balanced equation = 1 x 62 = 62g.

From the balanced equation above, 122g of Sr(OH)2 reacted with 62g of H2CO3.

Finally, we shall determine the limiting reactant as follow:

From the balanced equation above, 122g of Sr(OH)2 reacted with 62g of H2CO3.

Therefore, 12.5g of Sr(OH)2 will react with = (12.5 x 62)/122 = 6.35g.

We can see evidently from the calculations made above that it will take 6.35g out 32.55g of H2CO3 to react with 12.5g of Sr(OH)2. Therefore, Sr(OH)2 is the limiting reactant and H2CO3 is the excess reactant

5 0
3 years ago
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What type of molecule is acetylacetone?
Vlada [557]

Answer:

c. ketone

Explanation:

the answer is ketone

6 0
2 years ago
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