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Nadusha1986 [10]
1 year ago
6

What is the percent of Cu in CuSO4?

Chemistry
1 answer:
Alinara [238K]1 year ago
7 0

The mass percentage of the copper (Cu) in the compound CuSO₄ is 39.81%.

<h3>What is the mass percentage?</h3>

The percentage of an element in a compound can be determined as the number of parts by mass of that element present in 100 parts by mass of the given compound.

First, calculate the molecular mass of the given compound by the addition of the atomic masses of all the present elements in the molecular formula. Then, the percentage of the elements can be determined by dividing the total mass of the element by the molar mass of the compound multiplied by 100.

Given, the atomic mass of copper, sulfur, and oxygen is 63.55 g, 32.07 g, and 16.0g respectively.

The molecular mass of CuSO₄ =  63.55 + 32.07 + 4(16.0)  = 159.62 g.

The mass percentage of the Sulphur = (63.55/159.62) × 100 = 39.81%.

Therefore, the mass percentage of Copper is equal to 39To learn.

Learn more about  the mass percentage, visit here:

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Which structures perform similar functions in plant and animal cells?
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An analytical chemist is titrating of a solution of propionic acid with a solution of . The of propionic acid is . Calculate the
motikmotik

Answer:

Heres my attempt at this and hope it helps friend

.1372L * (.83M/L) = .114 mols propanoic acid

.06862L * (1.1M/L) = 0.0755 mols NaOH

using the henderson hasselbach equation

ph = pKa + log([A-]/[HA])

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ph = 4.89 + log(.0755/.114) = 4.72

Explanation:

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3 0
3 years ago
The theoretical yield of NaBr from
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the percent yield of the reaction is 100%.

The percent yield is calculated as the experimental yield divided by the theoretical yield x 100%:

% yield = actual yield / theoretical yield * 100%

% yield of a reaction in this case Rate

In this case, the molar mass of NaBr is 102.9 g / mol, as you know:

444 actual yield = 7.08 mol x 102.9 g / mol = 728.532 g

theoretical yield = 7.08 mol x 102.9 g / mol = 728.532 g

, Replaced by the definition of percent yield:

percent yield = 728.532 grams / 728.532 grams * 100%

percent yield = 100%

Finally, the percent yield of the reaction is 100%.

<h3 />

FeBr3 is iron bromide. Also known as iron bromide. Iron bromide is an ionic compound in which iron is in a +3 oxidation state.

Learn more about % yield here:brainly.com/question/27979178

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The charge of the stable ion of S and Li?
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