The answer is 10.5 kg m/s
Impulse (I) is the multiplication of force (F) and time interval (Δt): I = F · Δt
Force (F) is the multiplication of mass (m) and acceleration (a): F = m · a
Acceleration (a) can be expressed as change in velocity (v) divided by time interval (Δt): a = Δv/Δt
So:
a = Δv/Δt ⇒ F = m · a = m · Δv/Δt
F = m · Δv/Δt ⇒ I = m · Δv/Δt · Δt
Since Δt can be cancelled out, impulse can be expressed as:
I = m · Δv = m · (v2 - v1)
It is given:
m = 1.5 kg
v1 = 15 m/s
v2 = 22 m/s
I = 1.5 · (22 - 15) = 1.5 · 7 = 10.5 kgm/s.
Answer:
Maximum speed ( v ) = 10.4 m/s (Approx)
Explanation:
Given:
Amplitude A = 15.0 cm = 0.15 m
Frequency f = 11.0 cycles/s (Hz)
Find:
Maximum speed ( v )
Computation:
Angular frequency = 2πf
Angular frequency = 2π(11)
Angular frequency = 69.14
Maximum speed ( v ) = WA
Maximum speed ( v ) = 69.14 x 0.15
Maximum speed ( v ) = 10.371
Maximum speed ( v ) = 10.4 m/s (Approx)
Ions are particles formed when an atom of an element looses or gains electrons to attain a stable configuration.They are either positively charged (cations) or negatively charged (anions). Ionic crystals consists of ions bound together by electrostatic attraction forming a regular arrangement, geometric structure called crystal lattice. In an ionic solid the ions are held by strong attractive forces (tightly bound) and cannot move from their positions in the crystal structure and therefore, do not conduct electricity.
1 and 4 are tire.
2 and 3 are not.
Answer:
1.082 mm
Explanation:
From the question, we can see that we were given The following
Wavelength of the atoms, λ = 502 nm = 502*10^-9 m
Radius of the screen away from the double slit, r = 1.1 m
We know that Y(20) = 10.2 mm = 10.2*10^-3 m
d = (20 * R * λ) / Y(20)
d = (20 * 1.1 * 502*10^-9)/10.2*10^-3
d = 1.1*10^-5 / 10.2*10^-3
d = 1.082 mm
Therefore, we can say that the distance of separation between the two slits is 1.082 mm
