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Sergeu [11.5K]
3 years ago
5

4. A 15 V battery is connected to three capacitors in series. The capacitors have the following

Physics
1 answer:
Anastaziya [24]3 years ago
5 0
Vp = Vs 14.o V battery 3.96 ûF
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Two parallel conducting plates are connected to a constant voltage source. The magnitude of the electric field between the plate
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Answer:

The magnitude of the new electric field is <u>35820 N/C</u>.

Explanation:

Given:

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Original voltage = 'V' (Assume)

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Now, new voltage is three times original voltage. So, V_n=3V

New distance is 1/5 the original distance. So, d_n=\dfrac{d}{5}

Now, electric field between the parallel plates originally is given as:

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E_n=\frac{V_n}{d_n}\\\\E_n=\frac{3V}{\frac{d}{5}}\\\\E_n=15(\frac{V}{d})

Now, \frac{V}{d}=2388\ N/C. So,

E_n=15\times 2388=35820\ N/C

Therefore, the magnitude of the new electric field is 35820 N/C.

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How are steam powered boats different from sailboats
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