A 250 g block of ice is removed from the refrigerator at -8.0°C. How much thermal energy does the ice absorb as it warms to room
1 answer:
Answer:
Q = 114895 J
Explanation:
To find the thermal energy gained by the ice you use the following formula:
m: mass of the ice = 0.250kg
T2: final temperature = 22°C
T1: initial temperature = -8.0°C
Hf: heat of fusion of water = 3.34*10^5 J/kg
c: specific heat of water = 4186 J/kg
By replacing the values of the parameters you have:
where you have considered that ice melts completely
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Answer:
a) Frope= 71.7 N
b) Frope=6.7 N
Explanation:
In the figure the skier is simulated as an object, "a box".
a) At constant velocity we can say that the object is in equilibrium, so we apply the Newton's first law:
∑F=0
Frope=w*sen6.8°
Frope=71.71N
Take into account that w is the weight that is calculated as mass per gravitiy constant:
w=m*g
b) In this case the system has an acceleration of 0.109m/s2. Then, we apply Newton's second law of motion:
F=m*a
F=61.8Kg*0.109m/s2
Frope=6.73N
