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anygoal [31]
4 years ago
10

The overall equation for the cellular respiration of glucose is C6H12O6 + 6 O2 → 6 CO2 + 6 H2O + energy. C5H12O6 + 6 O2 → 5 CO2

+ 6 H2O + energy. 5 CO2 + 6 H2O → C5H12O6 + 6 O2 + energy. C6H12O6 + energy → 6 CO2+ 6 H2O + 6 O2. R
Chemistry
1 answer:
olga55 [171]4 years ago
4 0

Answer:

The answer to your question is: first option.

Explanation:

C6H12O6 + 6 O2 → 6 CO2 + 6 H2O + energy.  This option is correct, 1 molecule of glucose reacts with 6 molecules of oxygen and produces 6 molecules of carbon dioxide, six molecules of water and energy.

C5H12O6 + 6 O2 → 5 CO2 + 6 H2O + energy. This option is incorrect because glucose has 6 carbons not five.

5 CO2 + 6 H2O → C5H12O6 + 6 O2 + energy. This is the reaction of photosynthesis, it is the inverse reaction of cellular respiration.

C6H12O6 + energy → 6 CO2+ 6 H2O + 6 O2. This reaction does not exist.

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Answer:

Molality = 1.13 m

Explanation:

Molality is defined as the moles of the solute present in 1 kilogram of the solvent.

Given that:

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Molar mass of CH_3OH = 32.04 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{26.5\ g}{32.04\ g/mol}

Moles\ of\ CH_3OH= 0.8271\ moles

Mass of water = 735 g = 0.735 kg ( 1 g = 0.001 kg )

So, molality is:

m=\frac {0.8271\ moles}{0.735\ kg}

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4 0
3 years ago
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Answer:

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Explanation:

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<em />

M = (no. of moles of solute)/(V of the solution (L)).

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<em></em>

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