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AURORKA [14]
2 years ago
12

Which statement about the temperatures of phase changes and electrostatic forces holding the molecules is correct?(1 point)

Chemistry
1 answer:
lubasha [3.4K]2 years ago
4 0

The temperature at which phase changes occur is highly dependent on the electrostatic forces between the molecules in the substance.

The forces that hold molecules together are called intermolecular forces. These intermolecular forces affect the temperature at which phase changes occur. The  statement about phase changes and electrostatic forces that is correct is that; "the temperatures at which a substance changes phases indicate the relative strength of the forces between molecules in the substance."

There are three states of matter, solid liquid and gas. The order of intermolecular forces in all the states of matter are not the same. The order of strongest collective electrostatic forces to weakest collective electrostatic forces is; solid, liquid, gas.

When water boils, the forces between water molecules break, and the bonds between the atoms in water are unchanged.

When a sample of calcium carbonate is cooled, the forces strengthen, and the molecule structure becomes more rigid.

If the boiling point of acetone is lower than the boiling point of ethanol, then, the intermolecular forces in ethanol are stronger than the intermolecular forces in acetone.

Learn more about phase changes: brainly.com/question/671212

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5 0
2 years ago
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If the distance between two objects is decreased to - of the original
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Answer:

The new force will be \frac{1}{100} of the original force.

Explanation:

In the context of this problem, we're dealing with the law of gravitational attraction. The law states that the gravitational force between two object is directly proportional to the product of their masses and inversely proportional to the square of a distance between them.

That said, let's say that our equation for the initial force is:

F = G\frac{m_1m_2}{R^2}The problem states  that  the distance decrease to 1/10 of the original distance, this means:[tex]R_2 = \frac{1}{10}R

And the force at this distance would be written in terms of the same equation:

F_2 = G\frac{m_1m_2}{R_2^2}

Find the ratio between the final and the initial force:

\frac{F_2}{F} = \frac{G\frac{m_1m_2}{R_2^2}}{G\frac{m_1m_2}{R^2}}

Substitute the value for the final distance in terms of the initial distance:

\frac{F_2}{F} = \frac{G\frac{m_1m_2}{(\frac{R}{10})^2}}{G\frac{m_1m_2}{R^2}}

Simplify:

\frac{F_2}{F} = \frac{\frac{1}{100R^2}}{\frac{1}{R^2}}=\frac{1}{100}

This means the new force will be \frac{1}{100} of the original force.

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