3Zn(OH)₂ + 2H₃PO₄ → Zn₃(PO₄)₂ + 6H₂O
Explanation:
To balance this equation, we must understand that in every chemical reaction, the number of atoms is usually conserved.
The total number of atoms on the reactant and product sides must be equal and the same.
Zn(OH)₂ + H₃PO₄ → Zn₃(PO₄)₂ + H₂O
We are are going to use simple, solvable algebraic equations to balance this;
aZn(OH)₂ + bH₃PO₄ → cZn₃(PO₄)₂ + dH₂O
a, b,c and d are the number of coefficient that will balance this equation:
Conserving Zn ; a = 3c
O: 2a + 4b = 8c + d
H: 2a + 3b = 2d
P: b = 2c
let c = 1;
a = 3
b = 2
solving for d;
2d = 2(3) + 3(2)
d = 6
3Zn(OH)₂ + 2H₃PO₄ → Zn₃(PO₄)₂ + 6H₂O
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Answer:
dispersion.
Explanation:
The molecule, PF2Cl3 is trigonal bipyramidal. The dipoles in the molecule cancel out since there is a symmetric charge distribution around the molecule hence the resultant dipole moment of the molecule is zero.
If the molecule is nonpolar, then the dominant intermolecular forces present are the weak dispersion forces, hence the answer above.
Covalent substances have weaker intermolecular attractions.
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The balanced equation for the reaction between Ba(OH)₂ and HCl is ;
Ba(OH)₂ + 2HCl ----> BaCl₂ + 2H₂O
When equal volumes of both acid and base are added, the pH is 7 which means its neutral.
This means that the H⁺ ions and OH⁻ are equal and they have neutralised each other. All the ions have reacted to form water molecules.
Dissociation of base and acid are as follows;
Ba(OH)₂ ---> Ba²⁺ + 2OH⁻
1 mol of Ba(OH)₂ dissociates to 2 mol H⁺
HCl ---> H⁺ + Cl⁻
n moles of HCl give out n mol of H⁺ ions
H⁺ = OH⁻ which is why solution is neutral
then OH⁻ moles present are n mol
then Ba(OH)₂ moles present should be n/2 mol
molarity of HCl = 0.5 mol/L
since volumes are equal number of moles are directly proportional to molarity
molarity of Ba(OH)₂ = 0.5/2 = 0.25 M
