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2 years ago

A 4.0g Glass was heated from 5°C to 45°C after absorbing 32 J of heat. What is the specific heat of the glass?

Chemistry

1 answer:

IRINA_888 [86]2 years ago

3 0

Answer:

$c=0.2\ J/g^{\circ} C$

Explanation:

Given that,

Mass of a glass, m = 4 g

Initial temperature, $T_i=5^{\circ} C$

Final temperature, $T_f=45^{\circ} C$

Heat absorbed, Q = 32 J

We need to find the specific heat of the glass. The formula for the heat absorbed is given by :

$Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{32\ J}{4\ g\times (45-5)^{\circ} C}\\\\=0.2\ J/g^{\circ} C$

So, the required specific heat of the glass is $0.2\ J/g^{\circ} C$ .

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In your case, you know that your sample of gas occupies

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−

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Answer:

Following are the solution to this question:

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Please find the complete question in the attachment.

Start of Laboratory

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Ending of the Lab

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3 years ago

A 4.0g Glass was heated from 5°C to 45°C after absorbing 32 J of heat. What is the specific heat of the glass? ￼￼￼

A 4.0g Glass was heated from 5°C to 45°C after absorbing 32 J of heat. What is the specific heat of the glass?