Question

A 4.0g Glass was heated from 5°C to 45°C after absorbing 32 J of heat. What is the specific heat of the glass? 

Answer 1

Answer:

$c=0.2\ J/g^{\circ} C$

Explanation:

Given that,

Mass of a glass, m = 4 g

Initial temperature, $T_i=5^{\circ} C$

Final temperature, $T_f=45^{\circ} C$

Heat absorbed, Q = 32 J

We need to find the specific heat of the glass. The formula for the heat absorbed is given by :

$Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{32\ J}{4\ g\times (45-5)^{\circ} C}\\\\=0.2\ J/g^{\circ} C$

So, the required specific heat of the glass is $0.2\ J/g^{\circ} C$.