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MrRa [10]
4 years ago
13

A student who has trouble hearing and must have a written copy of class lectures in order to participate in class is considered

to have which of the following?
Physics
1 answer:
Scrat [10]4 years ago
5 0
<span>For this, the student has problems when participating in class discussions. </span>I believe that this type of student has a participation restriction disability. This disability refers to an individual who cannot focus or is not capable of participating in social activities.
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A 0.540-kg bucket rests on a scale. Into this bucket you pour sand at the constant rate of 56.0 g/s. If the sand lands in the bu
romanna [79]

Answer:

a) 12.8212 N

b) 12.642 N

Explanation:

Mass of bucket = m = 0.54 kg

Rate of filling with sand  = 56.0 g/ sec = 0.056 kg/s

Speed of sand = 3.2 m/s

g= 9.8 m/sec2

<u>Condition (a);</u>

Mass of sand = Ms = 0.75 kg

So total mass becomes = bucket mass + sand mass = 0.54 +0.75=1.29 kg

== > total weight = 1.29 × 9.8 = 12.642 N

Now impact of sand = rate of filling × velocity = 0.056 × 3.2 =  0.1792 kg. m /sec2=0.1792 N

Scale reading is sum of impact of sand and weight force ;

i-e

scale reading = 12.642 N+0.1792 N = 12.8212 N

<u>Codition (b);</u>

bucket mass + sand mass = 0.54 +0.75=1.29 kg

==>weight = mg = 1.29 × 9.8 = 12.642 N (readily calculated above as well)

6 0
3 years ago
if the distance moved by the effort is greater than the distance moved by the load, the machine is speed multiplier. TRUE/FALSE​
just olya [345]

Answer: TRUE

Explanation: I did it before

4 0
2 years ago
The initial concentration of N2O4 is 0.45M The system is heated and allowed to reach equilibrium. At equilibrium concentration o
Damm [24]

Answer : The value of equilibrium constant K_c for the following reaction will be, 2.4

Explanation :  Given,

Initial concentration of N_2O_4 = 0.45 M

Equilibrium concentration of NO_2 = 0.30 M

K_c is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The given balanced equilibrium reaction is,

N_2O_4(g)\rightleftharpoons 2NO_2(g)

As we know that the concentrations of pure solids are constant that means they do not change. Thus, they are not included in the equilibrium expression.

Actual concentration of NO_2 at equilibrium = 2\times 0.30M=0.6M

Concentration of N_2O_4 at equilibrium = [N_2O_4]-[NO_2]=0.45-0.30=0.15M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[NO_2]^2}{[N_2O_4]}

Now put all the given values in this expression, we get :

K_c=\frac{(0.6)^2}{(0.15)}

K_c=2.4

Therefore, the value of equilibrium constant K_c for the following reaction will be, 2.4

3 0
3 years ago
If 'P' represents white color flowers and 'p' represents purple color flowers, and you cross a PP plant with a pp plant, what wi
satela [25.4K]
The genotype for all offspring will be Pp making the flower color white.
4 0
3 years ago
If <br>1=5<br>2=10<br>3=15<br>4=20<br>what does 5 equal?
iogann1982 [59]
5 would be 25 if it continues in the same pattern
7 0
3 years ago
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