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ipn [44]
3 years ago
14

Which choice is the appropriate simplified form n restriction for the variable 12x^2 - 8x / 4x^2

Mathematics
1 answer:
tatiyna3 years ago
5 0
\frac{12x^{2} - 8x}{4x^{2}} = \frac{4x(3x-2)}{4x^{2}} = \frac{3x-2}{x} ,where 

x \neq 0
\\ \\B.   \frac{3x-2}{x} , x \neq 0
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A random sample of n = 45 observations from a quantitative population produced a mean x = 2.5 and a standard deviation s = 0.26.
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Answer:

P-value (t=2.58) = 0.0066.

Note: as we are using the sample standard deviation, a t-statistic is appropiate instead os a z-statistic.

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population mean μ exceeds 2.4.

Then, the null and alternative hypothesis are:

H_0: \mu=2.4\\\\H_a:\mu> 2.4

The significance level is 0.05.

The sample has a size n=45.

The sample mean is M=2.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.26.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.26}{\sqrt{45}}=0.0388

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t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{2.5-2.4}{0.0388}=\dfrac{0.1}{0.0388}=2.58

The degrees of freedom for this sample size are:

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This test is a right-tailed test, with 44 degrees of freedom and t=2.58, so the P-value for this test is calculated as (using a t-table):

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The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

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3 years ago
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Answletter A is correct.

Step-by-step explanation:

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Tpy6a [65]

Answer:

option A. 21 sec

Step-by-step explanation:

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