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Alik [6]
3 years ago
14

The length of a rectangle is 8 1/2 inches and the width is 3 1/4 inches. What is the ratio, using whole numbers, of the length t

o the width?
Mathematics
1 answer:
frosja888 [35]3 years ago
5 0
Short answer 34/13
Start by converting both to improper fractions.

8 1/2 = (2*8 + 1)/2 = 17/2

3 1/4 = (3*4 + 1)/4 = 13/4

Next set up a 4 layer fraction

\dfrac{\dfrac{17}{2}}{\dfrac{13}{4} }

Invert the lower fraction and multiply\dfrac{17}{2}* \dfrac{4}{13}

Cancel the 2 and the 4 leaving you with a 2 in the numerator.\dfrac{17*2}{13} =\dfrac{34}{13} 

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The first thing you should do in this case is to know how much paper you need to print for the 17 copies.
 We have then:
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 Then, you must calculate the number of reams you need:
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 answer
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Find the 12th term of the sequence -15,-9,-3, 3
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PLEASE GUYS HELP ITS DUE TONIGHT​
KATRIN_1 [288]

Answer:

20. AB = 42

21. BC = 28

22. AC = 70

23. BC = 20.4

24. FH = 48

25. DE = 10, EF = 10, DF = 20

Step-by-step explanation:

✍️Given:

AB = 2x + 7

BC = 28

AC = 4x,

20. Assuming B is between A and C, thus:

AB + BC = AC (Segment Addition Postulate)

2x + 7 + 28 = 4x (substitution)

Collect like terms

2x + 35 = 4x

35 = 4x - 2x

35 = 2x

Divide both side by 2

17.5 = x

AB = 2x + 7

Plug in the value of x

AB = 2(17.5) + 7 = 42

21. BC = 28 (given)

22. AC = 4x

Plug in the value of x

AC = 4(17.5) = 70

✍️Given:

AC = 35 and AB = 14.6.

Assuming B is between A and C, thus:

23. AB + BC = AC (Segment Addition Postulate)

14.6 + BC = 35 (Substitution)

Subtract 14.6 from each side

BC = 35 - 14.6

BC = 20.4

24. FH = 7x + 6

FG = 4x

GH = 24

FG + GH = FH (Segment Addition Postulate)

4x + 24 = 7x + 6 (substitution)

Collect like terms

4x - 7x = -24 + 6

-3x = - 18

Divide both sides by -3

x = 6

FH = 7x + 6

Plug in the value of x

FH = 7(6) + 6 = 48

25. DE = 5x, EF = 3x + 4

Given that E bisects DF, therefore,

DE = EF

5x = 3x + 4 (substitution)

Subtract 3x from each side

5x - 3x = 4

2x = 4

Divide both sides by 2

x = 2

DE = 5x

Plug in the value of x

DE = 5(2) = 10

EF = 3x + 4

Plug in the value of x

EF = 3(2) + 4 = 10

DF = DE + EF

DE = 10 + 10 (substitution)

DE = 20

4 0
3 years ago
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