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Vlad1618 [11]
4 years ago
5

Chemical equations need to be balanced in order to satisfy the law of

Chemistry
2 answers:
mafiozo [28]4 years ago
7 0

<u>Answer:</u> Every chemical equation follows law of conservation of mass.

<u>Explanation:</u>

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.  

This also means that total mass on the reactant side must be equal to the total mass on the product side.

Every balanced chemical equation follows law of conservation of mass.

<u>For Example:</u>  Formation of water

2H_2+O_2\rightarrow 2H_2O

Total mass on the reactant side = [2(2\times 1)+(2\times 16)]=36g/mol

Total mass on the product side = [2((2\times 1)+16)]=36g/mol

Hence, every chemical equation follows law of conservation of mass.

cupoosta [38]4 years ago
3 0
To satisfy the law of conservation of mass
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Explanation:

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4 0
3 years ago
What is the mass of a bar of aluminum with length 5.3cm, width 0.32 cm and height 2.34cm? The density of aluminum is 2.70g/cm3.
Tatiana [17]

Answer:

<h2>mass = 10.72 g</h2>

Explanation:

Density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

Making mass the subject we have

mass = Density \times volume

From the question

Density = 2.70 g/cm³

We assume that the aluminum is a cuboid

and volume of a cuboid is given by

Volume = length × width × height

length = 5.3 cm

width = 0.32 cm

height = 2.34 cm

Volume = 5.3 × 0.32 × 2.34 = 3.97 cm³

Substitute the values into the above and solve for the mass

We have

mass = 2.70 × 3.97

We have the final answer as

<h3>mass = 10.72 g</h3>

Hope this helps you

6 0
3 years ago
What is the importance of standardization in chemistry​
Anika [276]

Answer:

Standardisation is used to determine the concentration of a volumetric solution in order to achieve accurate and reliable titration results

5 0
4 years ago
The acetylene tank contains 35.0 mol C2H2, and the oxygen tank contains 84.0 mol O2.
harkovskaia [24]

Answer:- As per the question is asked, 35.0 moles of acetylene gives 70 moles of carbon dioxide but if we solve the problem using the limiting reactant which is oxygen then 67.2 moles of carbon dioxide will form.

Solution:- The balanced equation for the combustion of acetylene is:

2C_2H_2(g)+5O_2(g)\rightarrow 4CO_2(g)+2H_2O(g)

From the balanced equation, two moles of acetylene gives four moles of carbon dioxide. Using dimensional analysis we could show the calculations for the formation of carbon dioxide by the combustion of 35.0 moles of acetylene.

35.0molC_2H_2(\frac{4molCO_2}{2molC_2H_2})

= 70molCO_2

The next part is, how we choose 35.0 moles of acetylene and not 84.0 moles of oxygen.

From balanced equation, there is 2:5 mol ratio between acetylene and oxygen. Let's calculate the moles of oxygen required to react completely with 35.0 moles of acetylene.

35.0molC_2H_2(\frac{5molO_2}{2molC_2H_2})

= 87.5molO_2

Calculations shows that 87.5 moles of oxygen are required to react completely with 35.0 moles of acetylene. Since only 84.0 moles of oxygen are available, the limiting reactant is oxygen, so 35.0 moles of acetylene will not react completely as it is excess reactant.

So, the theoretical yield should be calculated using 84.0 moles of oxygen as:

84.0molO_2(\frac{4molO_2}{5molO_2})

= 67.2molCO_2

7 0
4 years ago
Read 2 more answers
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