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Juli2301 [7.4K]
3 years ago
9

Determine the boiling point of water at 620 mm Hg?

Chemistry
2 answers:
AfilCa [17]3 years ago
7 0
For example, at sea level the atmospheric pressure is 760 mm Hg<span> (also expressed as 760 torr, 101325 Pa, 101.3 kPa, 1013.25 mbar or 14.696 psi) and pure </span>water<span> boils at 100°C. However, in Calgary (approx. 1050m above sea level) the atmospheric pressure is approximately 670 </span>mm Hg<span>, and </span>water<span> boils at about 96.6°C.</span>
lara31 [8.8K]3 years ago
4 0

<u>Answer:</u> The boiling point of water at 620 mmHg is 81.58°C.

<u>Explanation:</u>

Boiling point is defined as the temperature at which liquid state starts to convert into gaseous state.

Boiling point of water at 1 atm pressure is 100°C

Converting 1 atm to mmHg, we use the conversion factor:

1 atm = 760 mmHg

To calculate the temperature at 620 mmHg, we apply unitary method:

At 760 mmHg, the boiling point of water is 100°C.

Then, at 620 mmHg, the boiling point of water will be = \frac{100^oC}{760mmHg}\times 620mmHg=81.58^oC

Hence, the boiling point of water at 620 mmHg is 81.58°C.

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The hydrochloride form of cocaine has a solubility of 1.00 g in 0.400 mL water. Calculate the molarity of a saturated solution o
Tanya [424]

Answer:

The molarity of the solution is 7.4 mol/L

Explanation:

From the question above

0.400 ml of water contains 1.00 g of hydrochloride form of cocaine

Therefore 1000 ml of water will contain x g of hydrochloride form of cocaine

                    x = 1000 / 0.400

                    x = 2500 g

2500g of hydrochloride form of cocaine is present in 1000 ml of water.

Mole of hydrochloride form of cocaine = mass /molar mass of hydrochloride

Mole of hydrochloride form of cocaine = 2500/339.8

                                                                = 7.4 mol

Molarity = mol/ volume in liter (L)

molarity = 7.4 /1

Molarity = 7.4 mol/L

6 0
3 years ago
Read 2 more answers
The terms Q and K refer to reaction components at non-equilibrium and equilibrium conditions, respectively. For a forward reacti
daser333 [38]

Answer:

The value of Q must be less than that of K.

Explanation:

The difference of K and Q can be understood with the help of an example as follows

         A ⇄ B

In this reaction A is converted into B but after some A is converted , forward reaction stops At this point , let equilibrium concentration of B be [B] and let equilibrium concentration of A be [A]

In this case ratio of  [B] and  [A]  that is

K =  [B] / [A] which is called equilibrium constant.

But if we measure the concentration of A and B ,before equilibrium is reached , then the ratio of the concentration of A and B will be called Q. As reaction continues concentration of A increases and concentration of B decreases. Hence Q tends to be equal to K.

Q = [B] / [A] . It is clear that Q < K before equilibrium.

If Q < K , reaction will proceed towards equilibrium or forward reaction will

proceed .

8 0
3 years ago
How many moles of Na2Cr2O7 contain 14 moles of oxygen atoms?
sergiy2304 [10]
The number of moles of sodium dichromate from the number of moles of oxygen atoms can be determined through stoichiometry. Using the molecular formula of the compound, Na2Cr2O7, 1 mole of the compound contains 7 moles of oxygen. Hence, 14 moles O2*(1 mole Na2Cr2O7/ 7 mole O2) is equal to 2 moles <span>Na2Cr2O7.</span>
7 0
4 years ago
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Can you help me with this with a solution
LuckyWell [14K]

The complete table is inserted.

A table is given,

Formulas used:

pH=  -log(H⁺)

pOH=  -log(OH⁻)

pH+ pOH=14

Calculations:

For A: (H⁺)=2×10⁻⁸M

Using the pH formula:

pH=  -log(H⁺)=-log(2×10⁻⁸)=7.69

pOH=14 - 7.69=6.3

Calculating OH concentration,

pOH=  -log(OH⁻)

6.3= -log(OH⁻)

(OH⁻)=5.011×10⁻⁷M

Hence, the nature of A is basic.

Similarily,

For B,

(OH⁻)=1×10⁻⁷

Using the pH formula:

pOH=  -log(OH⁻)= -log(1×10⁻⁷)=7

pH=14-7=7

Calculating H concentration,

pH=  -log(H⁺)

7= -log(H⁺)

(H⁺)=1×10⁻⁷M

Hence, the nature of B is neutral.

Similarily,

For C,

pH=12.3

Using the pH formula:

pOH=14-12.3=1.7

Calculating H concentration,

pH=  -log(H⁺)

12.3= -log(H⁺)

(H⁺)=5.011×10⁻¹³M

Calculating OH concentration,

pOH=  -log(OH⁻)

1.7= -log(OH⁻)

(OH⁻)=1.99×10⁻²M

Hence, the nature of C is Basic.

Similarily,

For D,

pOH=6.8

Using the pH formula:

pH=14-6.8=7.2

Calculating H concentration,

pH=  -log(H⁺)

7.2= -log(H⁺)

(H⁺)=6.309×10⁻⁸M

Calculating OH concentration,

pOH=  -log(OH⁻)

6.8= -log(OH⁻)

(OH⁻)=1.58×10⁻⁷M

Hence, the nature of D is basic.

Learn more about the acid and bases here:

brainly.com/question/16189013

#SPJ10

3 0
2 years ago
What would the hydroxide ion concentration be if the hydrogen ion concentration was 1 x 10-3 M?
Sonbull [250]

Answer:

1 x 10⁻¹¹ M

Explanation:

<u>(Step 1)</u>

Determine the pH.

pH = -log[H⁺]

pH = -log[1 x 10⁻³ M]

pH = 3

<u>(Step 2)</u>

Determine the pOH.

pH + pOH = 14

3 + pOH = 14

pOH = 11

<u>(Step 3)</u>

Determine the hydroxide (OH⁻) concentration.

[OH⁻] = 10^-pOH

[OH⁻] = 10⁻¹¹

[OH⁻] = 1 x 10⁻¹¹ M

3 0
2 years ago
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