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Juli2301 [7.4K]
3 years ago
9

Determine the boiling point of water at 620 mm Hg?

Chemistry
2 answers:
AfilCa [17]3 years ago
7 0
For example, at sea level the atmospheric pressure is 760 mm Hg<span> (also expressed as 760 torr, 101325 Pa, 101.3 kPa, 1013.25 mbar or 14.696 psi) and pure </span>water<span> boils at 100°C. However, in Calgary (approx. 1050m above sea level) the atmospheric pressure is approximately 670 </span>mm Hg<span>, and </span>water<span> boils at about 96.6°C.</span>
lara31 [8.8K]3 years ago
4 0

<u>Answer:</u> The boiling point of water at 620 mmHg is 81.58°C.

<u>Explanation:</u>

Boiling point is defined as the temperature at which liquid state starts to convert into gaseous state.

Boiling point of water at 1 atm pressure is 100°C

Converting 1 atm to mmHg, we use the conversion factor:

1 atm = 760 mmHg

To calculate the temperature at 620 mmHg, we apply unitary method:

At 760 mmHg, the boiling point of water is 100°C.

Then, at 620 mmHg, the boiling point of water will be = \frac{100^oC}{760mmHg}\times 620mmHg=81.58^oC

Hence, the boiling point of water at 620 mmHg is 81.58°C.

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Answer:

3.052 × 10^24 particles

Explanation:

To get the number of particles (nA) in a substance, we multiply the number of moles of the substance by Avogadro's number (6.02 × 10^23)

The mass of Li2O given in this question is as follows: 151grams.

To convert this mass value to moles, we use;

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