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Juli2301 [7.4K]
3 years ago
9

Determine the boiling point of water at 620 mm Hg?

Chemistry
2 answers:
AfilCa [17]3 years ago
7 0
For example, at sea level the atmospheric pressure is 760 mm Hg<span> (also expressed as 760 torr, 101325 Pa, 101.3 kPa, 1013.25 mbar or 14.696 psi) and pure </span>water<span> boils at 100°C. However, in Calgary (approx. 1050m above sea level) the atmospheric pressure is approximately 670 </span>mm Hg<span>, and </span>water<span> boils at about 96.6°C.</span>
lara31 [8.8K]3 years ago
4 0

<u>Answer:</u> The boiling point of water at 620 mmHg is 81.58°C.

<u>Explanation:</u>

Boiling point is defined as the temperature at which liquid state starts to convert into gaseous state.

Boiling point of water at 1 atm pressure is 100°C

Converting 1 atm to mmHg, we use the conversion factor:

1 atm = 760 mmHg

To calculate the temperature at 620 mmHg, we apply unitary method:

At 760 mmHg, the boiling point of water is 100°C.

Then, at 620 mmHg, the boiling point of water will be = \frac{100^oC}{760mmHg}\times 620mmHg=81.58^oC

Hence, the boiling point of water at 620 mmHg is 81.58°C.

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3 years ago
When the following reaction comes to equilibrium, will the concentrations of the reactants or products be greater? Does the answ
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Answer:

At equilibrium, the concentration of the reactants will be greater than the concentration of the products. This does not depend on the initial concentrations of the reactants and products.

Explanation:

The value of Kc gives us an idea of the extent of the reaction. A big Kc (Kc > 1) means that in the equilibrium there are more products than reactants, and the opposite happens for a small Kc (Kc < 1). The equilibrium is reached no matter what the initial concentrations are.

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How many moles of hydrogen ions are formed in the ionization of 0.250 moles of H2SO4?
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Answer:

The ionization of 0.250 moles of H₂SO₄ will produce 0.5 moles of H⁺ (hydrogen ion)

Explanation:

From the ionization of H₂SO₄, we have

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Hence, at 100% yield, one mole of H₂SO₄ produces two moles of H⁺ (hydrogen ion) and one mole of SO₄²⁻ (sulphate ion), therefore, 0.250 moles of H₂SO₄ will produce 2×0.250 moles of H⁺ (hydrogen ion) or 0.5 moles of H⁺ (hydrogen ion) and 0.25 moles of SO₄²⁻ (sulphate ion).

That is; 0.250·H₂SO₄ → 0.5·H⁺ + 0.250·SO₄²⁻.

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