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Juli2301 [7.4K]
3 years ago
9

Determine the boiling point of water at 620 mm Hg?

Chemistry
2 answers:
AfilCa [17]3 years ago
7 0
For example, at sea level the atmospheric pressure is 760 mm Hg<span> (also expressed as 760 torr, 101325 Pa, 101.3 kPa, 1013.25 mbar or 14.696 psi) and pure </span>water<span> boils at 100°C. However, in Calgary (approx. 1050m above sea level) the atmospheric pressure is approximately 670 </span>mm Hg<span>, and </span>water<span> boils at about 96.6°C.</span>
lara31 [8.8K]3 years ago
4 0

<u>Answer:</u> The boiling point of water at 620 mmHg is 81.58°C.

<u>Explanation:</u>

Boiling point is defined as the temperature at which liquid state starts to convert into gaseous state.

Boiling point of water at 1 atm pressure is 100°C

Converting 1 atm to mmHg, we use the conversion factor:

1 atm = 760 mmHg

To calculate the temperature at 620 mmHg, we apply unitary method:

At 760 mmHg, the boiling point of water is 100°C.

Then, at 620 mmHg, the boiling point of water will be = \frac{100^oC}{760mmHg}\times 620mmHg=81.58^oC

Hence, the boiling point of water at 620 mmHg is 81.58°C.

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The product of the nitration reaction will have a nitro group at which position with respect to the methyl group? Group of answe
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Answer:

Mostly Para

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First, let's assume that the molecule is the toluene (A benzene with a methyl group as radical).

Now the nitration reaction is a reaction in which the nitric acid in presence of sulfuric acid, react with the benzene molecule, to introduce the nitro group into the molecule. The nitro group is a relative strong deactiviting group and is metha director, so, further reactions that occur will be in the metha position.

Now, in this case, the methyl group is a weak activating group in the molecule of benzene, and is always ortho and para director for the simple fact that this molecule (The methyl group) is a donor of electrons instead of atracting group of electrons. Therefore for these two reasons, when the nitration occurs,it will go to the ortho or para position.

Now which position will prefer to go? it's true it can go either ortho or para, however, let's use the steric hindrance principle. Although the methyl group it's not a very voluminous and big molecule, it still exerts a little steric hindrance, and the nitro group would rather go to a position where no molecule is present so it can attach easily. It's like you have two doors that lead to the same place, but in one door you have a kid in the middle and the other door is free to go, you'll rather pass by the door which is free instead of the door with the kid in the middle even though you can pass for that door too. Same thing happens here. Therefore the correct option will be mostly para.

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You can also measure the volume of an object by measuring how much water it displaces. To do this you have to fill a measuring cylinder with enough water for the object to be completely submerged and take note of the volume. Then, add the object and note again the volume of the water+object. The difference between both is the volume of the object.

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