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PtichkaEL [24]
3 years ago
15

Determine the poh of 0.01 molar solution of carbonic acid

Chemistry
1 answer:
Veronika [31]3 years ago
3 0

Hello!

Data:

Molar Mass of H2CO3 (carbonic acid)

H = 2*1 = 2 amu

C = 1*12 = 12 amu

O = 3*16 = 48 amu

------------------------

Molar Mass of H2CO3 = 2 + 12 + 48 = 62 g/mol

Now, since the Molarity and ionization constant has been supplied, we will find the degree of ionization, let us see:

M (molarity) = 0.01 M (Mol/L) → 1*10^{-2}\:M

Use: Ka (ionization constant) = 4.4*10^{-7}

\alpha^2 (degree\:of\:ionization) = ?

Ka = M * \alpha^2

4.4*10^{-7} = 1*10^{-2}*\alpha^2

1*10^{-2}*\alpha^2 = 4.4*10^{-7}

\alpha^2 = \dfrac{4.4*10^{-7}}{1*10^{-2}}

\alpha^2 = 4.4*10^{-7-(-2)}

\alpha^2 = 4.4*10^{-7+2}

\alpha^2 = 4.4*10^{-5}

\alpha = \sqrt{4.4*10^{-5}}

\boxed{\alpha \approx 2.09*10^{-5}}

Now, we will calculate the amount of Hydronium [H3O+] in carbonic acid (H2CO3), multiply the acid molarity by the degree of ionization, we will have:

[ H_{3} O^+] = M* \alpha

[ H_{3} O^+] = 1*10^{-2}* 2.09*10^{-5}

[ H_{3} O^+] = 2.09*10^{-2-5}

\boxed{[ H_{3} O^+] = 2.09*10^{-7}}

And finally, we will use the data found and put in the logarithmic equation of the PH, thus:

Data:

pH = \:?

[ H_{3} O^+] = 2.09*10^{-7}

apply the data to formula

pH = - log[H_{3} O^+]

pH = - log[2.09*10^{-7}]

pH = 7 - log\:2.09

pH = 7 - 0.32

\boxed{pH = 6.68}

Note:. The pH <7, then we have an acidic solution (weak acid).

Now, let's find pOH by the following formula:

pH + pOH = 14

6.68 + pOH = 14

pOH = 14 - 6.68

\boxed{\boxed{pOH = 7.32}}\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

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<h3>Reaction stoichiometry</h3>

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By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

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The following rule of three can be applied: if by reaction stoichiometry 1 mole of CO₂ form 4 moles of CH₄, 85.1 moles of CO₂ form how many moles of CH₄?

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Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

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