Question

the standard for of the equation of a parabola is y=x^2+4x+11. What is the vertex for of the equation?

Answer 1

Convert to vertex form

or easier
for y=ax²+bx+c
the x value of the vertex is $\frac{-b}{2a}$
and the y value is found by subsituting the x value in for x

so
y=1x²+4x+11
a=1
b=4

the x value of the vertex is $\frac{-4}{2(1)}=\frac{-4}{2}=-2$

the y value is found by subsituting -2 for x
y=(-2)²+4(-2)+11
y=4-8+11
y=7

the vertex is (-2,7)