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Brums [2.3K]
3 years ago
6

The reaction PCl3(g)+Cl2(g)???PCl5(g)

Chemistry
2 answers:
ser-zykov [4K]3 years ago
8 0

Answer:

1) p(PCl3) =  0.66 atm

2) p(Cl2) =  0.66 atm

3) p(PCl5) = 0.038 atm

Explanation:

Step 1: Data given

Kp = 0.0870

Temperature = 300 °C

Pressure of PCl3 = 0.50 atm

Pressure of Cl2 = 0.50 atm

Pressure of PCl5 = 0.20 atm

Step 2: The balanced equation

PCl3(g) + Cl2(g) ⇆ PCl5(g)

Step 3: The pressure at equilibrium

p = [PCl5] / [PCl3] [Cl2]

Q = [0.20] / [0.50] [0.50]  = 0.8

Q >> Kp

The reaction will shift to the left to decrease the numerator PCl5

p(PCl3) = (0.50 + x) atm

p(Cl2) = (0.50 + x) atm

p(PCl5) = (0.20 - x) atm

Kp = (pPCl5) / (pPCl3) (pCl2)

0.0870 = (0.20-x) / (0.50+x) (0.50+x)

0.0870 (0.50+x)(0.50+x)  = (0.20-x)

0.0870 (0.25 + 1.0x + x²)= (0.20-x)

0.02175  + 0.087x + 0.087x² = 0.2 -x

0.087x² + 1.087x -0.17825 = 0

x= 0.1619

Step 4: The equilibrium partial pressures

p(PCl3) = (0.50 + x) atm = 0.50 + 0.1619 =  0.6619 atm

p(Cl2) = (0.50 + x) atm = 0.50 + 0.1619 =  0.6619 atm

p(PCl5) = (0.20 - x) atm = 0.20 - 0.1619 = 0.0381 atm

goldfiish [28.3K]3 years ago
5 0

Answer:

Just study the thing don't expect others to just answer the homework for you

Explanation:

If you truly are a good student then you should have asked your teacher in person or through email instead of asking on here. Not trying to be mean but you also have to understand that people on here have a life. :)

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<h3>1</h3>

Species shown in bold are precipitates.

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<h3>2</h3>

A double replacement reaction takes place only if it reduces in the concentration of ions in the solution. For example, the reaction between Ca(NO₃)₂ and KOH produces Ca(OH)₂. Ca(OH)₂ barely dissolves. The reaction has removed Ca²⁺ and OH⁻ ions from the solution.

Some of the reactions lead to neither precipitates nor gases. They will not take place since they are not energetically favored.


<h3>3</h3>

Compare the first and last row:

Both Ca(NO₃)₂ and Zn(NO₃)₂ react with KOH. However, between the two precipitates formed, Ca(OH)₂ is more soluble than Zn(OH)₂.

As a result, add the same amount of KOH to two Ca(NO₃)₂ and Zn(NO₃)₂ of equal concentration. The solution that end up with more precipitate shall belong to Zn(NO₃)₂.


<h3>4</h3>

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Cu(NO₃)₂ reacts with KI, but Ni(NO₃)₂ does not. Thus, add equal amount of KI to the two unknowns. The solution that forms precipitate shall belong to Cu(NO₃)₂.

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