All categories

3 years ago

NEED HELP ASAP

Mathematics

1 answer:

Mkey [24]3 years ago

4 0

Answer:

Option: A is correct.

A) a part of a line that has one endpoint and extends indefinitely in one direction

Step-by-step explanation:

" A ray is a line that starts at a given point and goes off for ever in some direction. It may pass through another point as it does so "

Hence, option A is correct.

( The definition of Ray is:

A) a part of a line that has one endpoint and extends indefinitely in one direction )

You might be interested in

HELP WITH ONE MATH QUESTION!!! 20 POINTS AND WILL MARK BRAINLIEST

Jobisdone [24]

Answer:

6/h = 10/40

Step-by-step explanation:

6/h = 10/40

8 0

2 years ago

1. What is the slope between the points (2,-5) and (8,3)? * Show work please

hjlf

Answer:

$\sf m = \dfrac{4}{3}$

Step-by-step explanation:

Given, $\sf (x_1, ~ y_1)$ = (2, -5) and $\sf (x_2, ~ y_2)$ = (8, 3)

The slope formula is, $\sf m = \dfrac{y_2 - y_1}{x_2 - x_1}$

$\sf m = \dfrac{3 - (-5)}{8 - 2}$

$\sf m = \dfrac{8}{6}$

$\bf m = \dfrac{4}{3}$

6 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2

Nimfa-mama [501]

First of all, we can observe that

$x^2-6x+9 = (x-3)^2$

So the expression becomes

$\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}$

This means that the expression is defined for every $x\neq 3$

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

$x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2$

Since we can't accept 3 as an answer, the actual solution set is

$(-\infty,-2] \cup [2,3) \cup (3,\infty)$

7 0

2 years ago

2067 Supp Q.No. 2a Find the sum of all the natural numbers between 1 and 100 which are divisible by 5. Ans: 1050

Alborosie

Answer:

1050

Step-by-step explanation:

Natural Numbers are positive whole numbers. They aren't negative, decimals, fractions. We can just divide 5 into 100 to find how many natural numbers go up to 100 and just add them but that is just to much.

There is a easier method.

E.g: Natural Numbers that are divisible by a Nth Number. is the same as adding the Nth Numbers to a multiple of that Nth Term. For example, let say we need to find numbers divisible by 2. We know that 4 is divisible by 2 because 4/2=2. We can add the Nth numbers which is 2 to 4. 4+2=6. And 6 is divisible by 2 because 6/2=3. We can call this a arithmetic series. A series which has a pattern of adding a common difference