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inna [77]
3 years ago
11

Which of the following correctly shows a neutralization reaction between a hydronium ion and a hydroxide ion?

Chemistry
2 answers:
Anika [276]3 years ago
3 0
I think the correct answer is, C.
Lynna [10]3 years ago
3 0

Answer: C) H_3O^++OH^-\rightarrow 2H_2O

Explanation: H^+ is hydrogen ion, H_3O^+ is hydronium ion and OH^- is hydroxide ion.

The question asks about the neutralization reaction between a hydronium ion and a hydroxide ion.

first equation is taking place between hydrogen ion and water so it is not the right choice.

Second equation is ionization of water into its ions so it is also not the correct choice.

Third equation is taking place between hydronium ion and hydroxide ion and so it is correct.

Fourth equation is taking place between water and ammonia and so it is also not correct.

So, the only correct one is C) H_3O^++OH^-\rightarrow 2H_2O .

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A sample of rutile, an ore of titanium consisting principally of TiO2(s), was found to be 65.2% TiO2(s) by mass, with the remain
Ivan

A sample of rutile, an ore of titanium consisting principally of TiO2(s), was found to be 65.2% TiO2(s) by mass, with the remainder being sand impurities. what is the minimum number of metric tons of the ore that must be processed to obtain 10.0 metric tons of titanium

Explanation:

Ore contains ---- 65.2% TiO_2

Mass% of titanium in TiO2 can be calculated as shown below:

mass percentage of Ti in TiO2=\frac{mass of Ti}{mass of TiO_2} *100\\=(47.86g/79.866g)* 100\\=59.9

Given 10.0 metric tons of titanium is required.

The mass of ore that should be processed can be calculated as shown below:

Mass of Ti = ore x TiO2 % x Ti mass %

10.0 x 1000 kg = M (mass of ore) x (65.2/100) x (59.9/100) Ti

=>M=(10.0 metric tons) / (0.652 x 0.599)

=>M=25.6 metric tons

Hence, the mass of ore required is 25.6 metric tons.

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