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inna [77]
3 years ago
11

Which of the following correctly shows a neutralization reaction between a hydronium ion and a hydroxide ion?

Chemistry
2 answers:
Anika [276]3 years ago
3 0
I think the correct answer is, C.
Lynna [10]3 years ago
3 0

Answer: C) H_3O^++OH^-\rightarrow 2H_2O

Explanation: H^+ is hydrogen ion, H_3O^+ is hydronium ion and OH^- is hydroxide ion.

The question asks about the neutralization reaction between a hydronium ion and a hydroxide ion.

first equation is taking place between hydrogen ion and water so it is not the right choice.

Second equation is ionization of water into its ions so it is also not the correct choice.

Third equation is taking place between hydronium ion and hydroxide ion and so it is correct.

Fourth equation is taking place between water and ammonia and so it is also not correct.

So, the only correct one is C) H_3O^++OH^-\rightarrow 2H_2O .

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The answer should be Pure substance
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What percent of earths total volume is the crust
vlada-n [284]

1%

Explanation:

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7 0
3 years ago
40.3 degrees Fahrenheit. Each hour the temperature decreases by 2.09 What is the
Murrr4er [49]
ANSWER

36.12 degrees fahrenheit
6 0
3 years ago
If δh = -70.0 kj and δs = -0.500 kj/k , the reaction is spontaneous below a certain temperature. calculate that temperature. exp
Nina [5.8K]
Answer is: temperature must be less than 140 K.
Gibbs free energy (G) determines if reaction will proceed spontaneously. <span>If the value of G is a negative, the reaction is spontaneous. <span>ΔG = ΔH - T·ΔS.
</span></span>ΔH = -70.00 kJ.
ΔS = -0.500 kJ/K.
-70 kJ = T · (-0.5 kJ/K).
T = -70.00 kJ ÷ (-0.500 kJ/K).
T = 140 K. 
6 0
3 years ago
Calculate each of the following quantities.<br> (a) mass in kilograms of 3.7 x 1020 molecules of NO2
HACTEHA [7]

Answer:

The answer to your question is:  0.028 kg of NO2

Explanation:

Data

3.7 x 10²⁰ molecules of NO2 in kg

MW of NO2 = 14 + (16 x 2) = 14 + 32 = 46 kg

                   1 mol of NO2 ---------------------  6.023 x 10 ²³ molecules

                   x                     --------------------- 3.7 x 10²⁰ molecules

                   x = 3.7 x 10²⁰ x 1 / 6.023 x 10 ²³

                   x = 0.00061 mol

         

                 1 mol of NO2 ---------------------  46 kg of NO2

                 0.00061 mol     ------------------    x

                 x = 0.00061 x 46/1

                x = 0.028 kg of NO2

7 0
3 years ago
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