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Sindrei [870]
2 years ago
13

Write oxide of Na, Fe, Cu Help​

Chemistry
1 answer:
vladimir1956 [14]2 years ago
6 0

Answer:

Na2O, Fe2O3, CuO

Explanation:

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Which label belongs in the area marked X? can reproduce by budding can reproduce by fragmentation with regeneration reproduce in
marusya05 [52]

Answer:

Nucleus.

Explanation:

The sponge is a multicellular organism that consists of pores that allows water to move through the body. Sponges belong to the kingdom Animalia and phylum Porifera. Sponges can reproduce by budding. Sponges are placed in kingdom Animalia because they are unable to make their own food, made of more than one cell, and absence of cell wall.

4 0
2 years ago
How many grams of Cl are in 525g of CaCl2
Tema [17]

First we determine the moles CaCl2 present:

525g / (110.9g/mole) = 4.73 moles CaCl2 present 

Based on stoichiometry, there are 2 moles of Cl for every mole of CaCl2:<span>
(2moles Cl / 1mole CaCl2) x 4.73 moles CaCl2 = 9.47 moles Cl </span>

Get the mass:<span>
<span>9.47moles Cl x 35.45g/mole = 335.64 g Cl</span></span>

8 0
3 years ago
प्रश्न 5. 'पुष्प की अभिलाषा' कविता में पुष्प के दवारा क्या अभिलाषा व्यक्त की गई ​
Kay [80]
Please ask in English
4 0
2 years ago
Give the numbers of significant figures indicated 60.1<br><br> 0 <br> 3 <br> 1 <br> 2
denpristay [2]
3 significant figures
4 0
2 years ago
Read 2 more answers
You need to prepare 150 mL of 0.1 M solution of silver chloride. How much silver chloride is required?
Rudiy27

Answer:

amount of silver chloride required is 0.015 moles or 2.1504 g

Explanation:

0.1M AgCL means 0.1mol/dm³ or 0.1mol/L

1L = 1000mL

if 0.1mol of AgCl is contained in 1000mL of solution

then x will be contained in 150mL of solution

cross multiply to find x

x = (0.1*150)/1000

x= 0.015 moles

moles of silver chloride present in 150 mL of solution is 0.15 moles

To convert this to grams, simply multiply this value by the molar mass of silver chloride

molar mass of silver chloride AgCl =107.86 + 35.5

                                                     =143.36 g/mol

mass of AgCl = moles *molar mass

                       =0.015*143.36

                        =2.1504g

                        =

4 0
2 years ago
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