The activity coefficient of h is 0.05
The ph of the solution is 2.08
To find the activity coefficient, apply the concept of ionic equilibrium
h( activity coefficient)= 1/2CZ²
C is the concentration of species
Z is the charge on individual species
<em>h= 1/2( 0.01 x1²+ 0.04x (-1)²+0.01 x1²+0.04x (-1)²)</em>
<em>h= 0.05 </em>
For the pH of the solution, apply the formula
<em>pH= -log( H⁺x0.83)</em>
<em>pH = - log(0.01x0.83)</em>
<em>= 2.08</em>
To learn more about the pH of the solution, visit brainly.com/question/26767292
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D. is the answer
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