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serg [7]
2 years ago
15

The process that causes a spark to occur when the discharge wand is close to the Van de Graaff generator is similar to the proce

ss that causes lightning to form. Use what you have learned about the tendency of potential energy to decrease to try to explain how lightning occurs.
Chemistry
1 answer:
guajiro [1.7K]2 years ago
4 0

Answer:

Lighter, positively charged particles form at the top of the cloud. Heavier, negatively charged particles sink to the bottom of the cloud. When the positive and negative charges grow large enough, a giant spark - lightning - occurs between the two charges within the cloud.

Explanation:

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What is the formula mass for sodium chloride?
Zigmanuir [339]
Atomic mass of sodium is 22.9 g/mol
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3 0
3 years ago
The molarity of an aqueous sodium phosphate solution is 0.650 M. What is the molality of sodium ions present in this solution? T
netineya [11]

Answer:

molality of sodium ions is 1.473 m

Explanation:

Molarity is moles of solute per litre of solution

Molality is moles of solute per kg of solvent.

The volume of solution = 1 L

The mass of solution = volume X density = 1000mL X 1.43 = 1430 grams

The mass of solute = moles X molar mass of sodium phosphate = 0.65X164

mass of solute = 106.6 grams

the mass of solvent = 1430 - 106.6 = 1323.4 grams = 1.3234 Kg

the molality = \frac{moles of solute}{mass of solvent in kg}=\frac{0.65}{1.323}= 0.491m

Thus molality of sodium phosphate is 0.491 m

Each sodium phosphate of molecule will give three sodium ions.

Thus molality of sodium ions = 3 X 0.491 = 1.473 m

7 0
3 years ago
Please help, with step by step work
natali 33 [55]

\qquad ☀️\pink{\bf{ {Answer  = \: \:   85.57g }}}

Molar mass of \bf Cu_2O

\qquad \twoheadrightarrow\sf 63.546 \times 2 +16

\qquad \pink{\twoheadrightarrow\bf 143.092 g}

<u>As we know</u>–

1 mol =\bf 6.02×10^{23} formula units

1 mol\bf Cu_2O = 143.092 g = \bf 6.02×10^{23}formula units

Henceforth –

\bf 3.60×10^{23} formula units \bf Cu_2O–

\qquad \sf :\implies \dfrac{143.092 \times3.60×10^{23  }}{6.02×10^{23}}

\qquad \sf :\implies \dfrac{143.092 \times3.60×\cancel{10^{23  }}}{6.02×\cancel{10^{23}}}

\qquad \pink{:\implies\bf 85.57 g}

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Answer:

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Write a balanced chemical equation for the formation of magnesium oxide, mg0, from magnesium and oxygen
swat32
This picture explains:

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3 years ago
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