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Yuliya22 [10]
3 years ago
14

Find the mass of 3.00 mol of acetic acid, C2H4O2

Chemistry
1 answer:
Alinara [238K]3 years ago
4 0
Molar mass acetic acid:

C₂H₄O₂ = 12 * 2 + 1 * 4 + 16 * 2 = 60.

n = mass / molar mass

3.00 = m / 60.0

m = 3.00 * 60.0

m = 180 g of <span>C₂H₄O₂

hope this helps!</span>
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How many grams of sodium hydroxide are needed to completely react with 50.0 grams of H2SO4?
Goryan [66]

Answer:

48.0 grams of NaOH I believe

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3 years ago
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What properties of matter are intensive independent of their size
Paha777 [63]

Answer:

temperature, refractive index, density, and hardness of an object

Explanation:

it is a bulk property, meaning that it is a physical property of a system that does not depend on the system size or the amount of material in the system

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3 years ago
Why does the sun appear very large compared to the other stars
Ivanshal [37]

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the other stars are much farther away from Earth than our sun

6 0
3 years ago
What is the Percent yield is 4.65 got copper is produced by 1.87 percent yield is 4.65 got copper is produced when 1.87 grams of
marta [7]

Answer:

Percent yield = 69.4%

Explanation:

Given data:

Percent yield  = ?

Actual yield of copper = 4.65 g

Mass of aluminium = 1.87 g

Mass of copper sulfate = excess

Solution:

Chemical equation:

2Al + 3CuSO₄   →   Al₂(SO₄)₃ + 3Cu

Number of moles of Aluminium:

Number of moles = mass/ molar mass

Number of moles = 1.87 g/27 g/mol

Number of moles = 0.07 mol

Now we will compare the moles of Al with copper.

                 Al           :            Cu

                   2           :              3

                0.07         :              3/2×0.07 =0.105 mol                    

Mass of Copper:(Theoretical yield)

Mass = Number of moles × molar mass

Mass = 0.105 mol × 63.5 g/mol

Mass = 6.7 g

Percent yield:

Percent yield = Actual yield / theoretical yield × 100

Percent yield = 4.65 g/ 6.7 g × 100

Percent yield = 69.4%

4 0
4 years ago
For each of the following sublevels, give the n and l values and the number of orbitals: (a) 5s; (b) 3p; (c) 4f
OverLord2011 [107]

Answer:

(a) 5s. n = 5. Sublevel s, l = 0. Number of orbitals = 1

(b) 3p. n = 3. Sublevel p, l = 1. Number of orbitals = 3

(c) 4f. n =4. Sublevel f, l = 3. Number of orbitals = 7

Explanation:

The rules for electron quantum numbers are:

1. Shell number, 1 ≤ n

2. Sublevel number, 0 ≤ l ≤ n − 1

So,

(a) 5s. n = 5, shell number 5. Sublevel s, l = 0. Number of orbitals = 2l +1 = 1

(b) 3p. n = 3, shell number 3. Sublevel p, l = 1. Number of orbitals = 2l +1 = 3

(c) 4f. n =4, shell number 4. Sublevel f, l = 3. Number of orbitals =  2l +1 = 7

6 0
3 years ago
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