All categories

4 years ago

Which form of bonding has unequal sharing of electrons between two elements?

Chemistry

2 answers:

Katen [24]4 years ago

7 0

The answer to this is D.

btw, i (shane) got deleted

Vlad1618 [11]4 years ago

6 0

Hello!

Your answer would be polar covalent.

Covalent bonds are where two atoms come together, and share electrons between each other, and are therefore, bonded.

In some cases of molecules that are bonded with a covalent bond, one of the atoms is more, you could call it selfish, and takes more of the electrons. A prime example of this is H20, or water. One of the atoms takes the electrons for longer, and therefore has a more negative charge because electrons are counted as negative charges.

This bond where an atom "hogs" electrons, is called a polar covalent bond, respective to the changing charges for the atoms.

So your answer is d.

Hope this helped!

You might be interested in

Phytoplankton are microscopic photosynthesizing organisms that typically live in the upper layers of the ocean. What trophic lev

alex41 [277]

Answer:

Primary producers

Explanation:

Phytoplankton belong to the primary producers trophic level. Beings of the other levels gain energy from phytoplankton. Phytoplankton are also capable of transforming inorganic carbon into protoplasm.

4 0

4 years ago

A model used for the yield Y of an agricultural crop as a function of the nitrogen level N in the soil (measured in appropriate

lisov135 [29]

Answer:

It is 3.

Explanation:

The model written correctly is:

$Y=\frac{kN}{9+N^2}$

This is a mathematical question, instead of a chemistry question, and you should use calculus to find the nitrogen level that gives the best yield, since this is an optimization problem.

The best yield is the maximum yield, and the maximum, provided that it exists, is found using the first derivative and making it equal to zero: Y' = 0

To find Y' you must use the quotient rule.

$Y'=\frac{(kN)'(9+N^2)- (kN)(9+N^2)'}{(9+N^2)^2}\\ \\Y'=\frac{k(9+N^2)-kN(2N)}{(9+N^2)^2}\\ \\Y'=\frac{9k + kN^2 - 2kN^2}{(9 + N^2)^2}=\frac{9k-kN^2}{(9+N^2)^2}$

Now make Y' = 0

The denominator is never equal to zero, because it is always positive and greater than 9.

Make the numerator equal to zero:

9k - kN² = 0

Factor: k (9 - N²) = 0

Since k is a positve constant, it is not equal to zero, and the other factor, 9 - N², must be equal to zero:

9 - N² = 0 ⇒ (3 - N) (3 + N) = 0

⇒ 3 - N = 0 or 3 + N = 0 ⇒ N = 3 or N = -3.

Since N is nitrogen level, it cannot be negative and the only valid answer is N = 3.

You can prove that it is a maximum (instead of a minimum) finding the second derivative or testing some points around 3 (e.g. 2.5 and 3.5).

8 0

3 years ago

What kind of reaction is this? 2Li + Cl2 —> 2LiCl

Leni [432]

Answer:

synthesis

Explanation:

8 0

3 years ago

Read 2 more answers

Consider the relationship (y+3)2 = b/(x-2), where y and x are variables and bis a constant. On rectangular coordinate paper, wha

Nikolay [14]

Answer:

(-1) is the slope of a graph of In(y+3) on the vertical axis versus In(x-2) on the horizontal axis.

Explanation:

$\frac{(y+3)}{2} = \frac{b}{(x-2)}$

Taking natural logarithm on both the sides:

$\ln [(y+3)]-\ln[2]=\ln [b]-\ln [(x-2)]$

$\ln [(y+3)]=\ln[2]+\ln [b]-\ln [(x-2)]$

$\ln [(y+3)]=\ln {[2\times b]-\ln [(x-2)]$

Slope intercept form is generally given as:

$y=mx+c$

m = slope, c = intercept on y axis or vertical axis

On rearranging equation:

$\ln [(y+3)]=(-1)\times \ln [(x-2)]+\ln {2b}$

y = ln [(y+3)], x = ln [(x-2)], m=-1 , c = ln 2b

(-1) is the slope of a graph of In(y+3) on the vertical axis versus In(x-2) on the horizontal axis.

8 0

3 years ago

A solution of water (kf=1.86 ∘c/m) and glucose freezes at − 2.15 ∘c. what is the molal concentration of glucose in this solution

Reil [10]

1.16 moles/liter The equation for freezing point depression in an ideal solution is Î”TF = KF * b * i where Î”TF = depression in freezing point, defined as TF (pure) â’ TF (solution). So in this case Î”TF = 2.15 KF = cryoscopic constant of the solvent (given as 1.86 âc/m) b = molality of solute i = van 't Hoff factor (number of ions of solute produced per molecule of solute). For glucose, that will be 1. Solving for b, we get Î”TF = KF * b * i Î”TF/KF = b * i Î”TF/(KF*i) = b And substuting known values. Î”TF/(KF*i) = b 2.15âc/(1.86âc/m * 1) = b 2.15/(1.86 1/m) = b 1.155913978 m = b So the molarity of the solution is 1.16 moles/liter to 3 significant figures.

7 0

3 years ago