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Sav [38]
3 years ago
13

Describe the properties of ammonium lauryl sulfate that make it a feasible surfactant

Chemistry
1 answer:
Basile [38]3 years ago
4 0

Answer:

Acidic inorganic salts, such as AMMONIUM LAURYL SULFATE, are generally soluble in water. The resulting solutions contain moderate concentrations of hydrogen ions and have pH's of less than 7.0. They react as acids to neutralize bases.

Explanation:

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Other than reducing greenhouse gas emissions, why would an entity switch to an alternative energy solution
Alika [10]

Answer:

renewable energy sources such as solar and wind DONT emit carbon dioxide and other greenhouse gases that contribute to global warming

Explanation:

8 0
2 years ago
Determine the mass of sodium carbonate required to produce 23.4g of sodium chloride when it reacts with excess hydrochloric acid
Leni [432]
The balanced chemical reaction for the described reaction above is,
                          Na2CO3 + 2HCl ---> 2NaCl + H2CO3
From the reaction, 1 mole of Na2CO3 is needed to produce 2 moles of NaCl. In terms of mass, 106 grams of Na2CO3 are needed to produce 116.9 grams of NaCl. From this,
                (23.4 g NaCl) x (106 g Na2CO3 / 116.9 NaCl = 21.22 g Na2CO3
Thus, approximately 21.22 g Na2CO3 is needed for the desired reaction. 
8 0
3 years ago
3. If the sun heats my car from a temperature of 20.0 C to a temperature of 55° C, what will the
Katyanochek1 [597]

Answer:

I would try but i just need points good luck tho

5 0
2 years ago
Both of the sulfur-oxygen double bonds in so2 is polar. in which direction should the polarity arrows point
kodGreya [7K]

Answer:

Away from the central sulfur atom.

Explanation:

4 0
3 years ago
Read 2 more answers
2-A gas sample is found to contain 39.10% carbon, 7.67% hydrogen, 26.11%
aleksandrvk [35]

The molecular formula :

C₆H₁₄O₃PF

<h3>Further explanation</h3>

Given

39.10% carbon, 7.67% hydrogen, 26.11%  oxygen, 16.82% phosphorus, and 10.30% fluorine.

Required

The molecular formula

Solution

mol ratio :

C = 39.1 : 12 = 3.258

H = 7.67 : 1 = 7.67

O = 26.11 : 16 = 1.632

P = 16.82 : 31 = 0.543

F = 10.3 : 19 = 0.542

Divide by 0.542

C = 6

H : 14

O = 3

P = 1

F = 1

The empirical formula :

C₆H₁₄O₃PF

(The empirical formula)n = the molecular formula

(C₆H₁₄O₃PF)=184.1

(6.12+14.1+3.16+31+19)n=184.1

(184)n=184.1

n = 1

3 0
3 years ago
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