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3 years ago

Describe the properties of ammonium lauryl sulfate that make it a feasible surfactant

Chemistry

1 answer:

Basile [38]3 years ago

4 0

Answer:

Acidic inorganic salts, such as AMMONIUM LAURYL SULFATE, are generally soluble in water. The resulting solutions contain moderate concentrations of hydrogen ions and have pH's of less than 7.0. They react as acids to neutralize bases.

Explanation:

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How many atoms are in 87.1 g of nickel?

devlian [24]

The exact answer is 511.219514

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3 years ago

What volume of oxygen at STP will be produced if the following reaction absorbed 275 kJ of heat?

defon

Answer:

Explanation:okay siejejeikeje

6 0

3 years ago

A sample of gas contains 0.1900 mol of CO(g) and 0.1900 mol of NO(g) and occupies a volume of 22.0 L. The following reaction tak

worty [1.4K]

Answer:

V₂ = 16.5 L

Explanation:

To solve this problem we use Avogadro's law, which applies when temperature and pressure remain constant:

V₁/n₁ = V₂/n₂

In this case, V₁ is 22.0 L, n₁ is [mol CO + mol NO], V₂ is our unknown, and n₂ is [mol CO₂ + mol N₂].

n₁ = mol CO + mol NO = 0.1900 + 0.1900 = 0.3800 mol

We use the reaction to calculate n₂:

2CO(g) + 2NO(g) → 2CO₂(g) + N₂(g)

mol CO₂:

0.1900 mol CO * $\frac{2molCO_{2}}{2molCO} =$ 0.1900 mol CO₂

mol N₂:

0.1900 mol NO * $\frac{1molN_{2}}{2molNO} =$ 0.095 mol N₂

n₂ = mol CO₂ + mol N₂ = 0.1900 + 0.095 = 0.2850 mol

Calculating V₂:

22.0 L / 0.3800 mol = V₂ / 0.2850 mol

V₂ = 16.5 L

3 0

4 years ago

6.) Choose all of the following that are TRUE regarding the Ideal Gas Law.

Cerrena [4.2K]

Answer:

All temperatures must be in Kelvins.

Explanation:

What you have to know;

When Pressure is in atm units

Temperature must be in Kelvins.
Volume must be in cubic centimetres.
R = 0.0813

When Pressure is in Pascals or N/m^2

Temperature must be in Kelvins.
Volume must be in cubic metres.
R = 8.314

4 0

3 years ago

How many liters of NH 3 are needed to react completely with 30.0 L of NO (at STP)?

aleksklad [387]

Answer:

20.8 Lof NH₃ are needed for the reaction

Explanation:

This is the reaction:

4 NH₃ + 6 NO → 5N₂ + 6H₂O

and the info. we need

Ammonia density = 0,00073 g/mL

Let's determine the moles of NO at STP by the Ideal Gases Law equation

P . V = n . R .T

1atm . 30L = n . 0.082 . 273K

(1atm . 30L) / (0.082 . 273K) = n → 1.34 moles of NO

Let's find out the amount of ammonia that should react

6 mol of NO react with 4 mol of ammonia

1.34 mol of NO will react with (1.34 .4)/6 = 0.893 moles of ammonia

Molar mass NH₃ = 17 g/m

0.893 mol . 17 g/m = 15.19 g of ammonia

Ammonia density = 0,00073 g/mL = NH₃ mass / NH₃ volume

0,00073 g/mL = 15.19 g / NH₃ volume

NH₃ volume = 15.19 g / 0,00073 g/mL → 20805.5 mL ⇒ 20.8 L

6 0

3 years ago