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denis-greek [22]
3 years ago
14

A pressure cooker is a pot whose lid can be tightly sealed to prevent gas from entering or escaping. even without knowing how bi

g the pressure cooker is, or what altitude it is being used at, we can make predictions about how much force the lid will experience under different conditions.
Physics
1 answer:
ankoles [38]3 years ago
5 0
Even without knowing the size of the pressure cooker or the altitude at which the pressure cooker will be used, we can easily determine the force on the lid by experience because just as boiling water, the amount of pressure inside the vessel (in this case, the cooker) increases as the temperature increases. 
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Susan and Hannah are each riding a swing. Susan has a mass of 25 kilograms, and Hannah has a mass of 30 kilograms. Susan’s swing
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Speed has a greater effect than mass
4 0
3 years ago
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Need help!!! A charge of 8.5 × 10–6 C is in an electric field that has a strength of 3.2 × 105 N/C. What is the electric force a
ddd [48]
B is the right answer. Multiply numbers you get the answer
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3 years ago
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Time (s)
olya-2409 [2.1K]

The moon orbiting the Earth

Explanation:

The motion of the moon orbiting the earth is a circular motion. Circular motion is simply the motion of an object in circle at constant speed.

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7 0
3 years ago
A box of mass 50 kg is pushed hard enough to set it in motion across a flat surface. Then a 99-N pushing force is needed to keep
vitfil [10]

Answer:

0.20

Explanation:

The box is moving at constant velocity, which means that its acceleration is zero; so, the net force acting on the box is zero as well.

There are two forces acting in the horizontal direction:

- The pushing force: F = 99 N, forward

- The frictional force: F_f=\mu mg, backward, with

\mu coefficient of kinetic friction

m = 50 kg mass of the box

g = 9.8 m/s^2 gravitational acceleration

The net force must be zero, so we have

F-F_f = 0

which we can solve to find the coefficient of kinetic friction:

F-\mu mg=0\\\mu = \frac{F}{mg}=\frac{99 N}{(50 kg)(9.8 m/s^2)}=0.20

7 0
3 years ago
An engine does 10 J of work and exhausts 25 J of waste heat during each cycle.
noname [10]
The thermal efficiency is defined as follows

\eta = 1 - \frac{Q_{\text{out}}}{Q_\text{in}},

and the energy which is put into the system is

Q_{\text{in}} = W_\text{out} + Q_\text{out}.

In your case Q_\text{in} = 25 \text{ J},W_\text{out}=10 \text{ J}.

So Q_\text{out}=10 \text{ J} which gives an efficiency of

\eta = 1 - \frac{10 \text{ J}}{25 \text { J}} = 0.6 = 60 \%.





4 0
3 years ago
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