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AnnyKZ [126]
3 years ago
9

Reaction is

Chemistry
1 answer:
-Dominant- [34]3 years ago
7 0
According  to the task, you  are proveded with patial pressure of CO2 and graphite, and here is complete solution for the task :
At first you have to find n1 =moles of CO2 and n2 which are moles of C 
<span>The you go :
</span>CO2(g) + C(s) \ \textless \ =\ \textgreater \  2CO(g)

n1 n2 0
-x -x +2x
n1-x n2-x 2x Kp=P^2 (CO)/Pco2
After that you have to use the formula PV=nRT
 Kp=(2x)^2/n1-x
Then you have to solve x, and for that you have to use <span>RT/V
And to find total values:</span>P(total)=n(total)*R*T/V
I am absolutely sure that this would be helpful for you.
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3. Two different compounds are formed by the elements carbon and oxygen. The first compound contains 42.9% by mass carbon and 57
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Answer:

The law of multiple proportions is the third postulate of Dalton's atomic theory. It states that the masses of one element which combine with a fixed mass of the second element are in a ratio of whole numbers.

Therefore, the masses of oxygen in the two compounds that combine with a fixed mass of carbon should be in a whole number ratio. In 100 grams of the first compound (100 is chosen to make calculations easier), there are 57.1 grams oxygen and 42.9 grams carbon. The mass of oxygen (O) per gram of carbon (C) is:

57.1 g O / 42.9 g C = 1.33 g O per g C

In the 100 grams of the second compound, there are 72.7 grams of oxygen (O) and 27.3 grams of carbon (C). The mass of oxygen per gram of carbon is:

72.7 g O / 27.3 g C = 2.66 g O per g C

Dividing the mass O per g C of the second (larger value) compound:

2.66 / 1.33 = 2

This means that the masses of oxygen that combine with carbon are in a 2:1 ratio. The whole-number ratio is consistent with the law of multiple proportions.

Explanation:

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Determine the number of moles NH41+ in 3 moles of (NH4)3PO4.
fomenos
(NH₄)₃PO₄ is a strong electrolyte which fully dissociates into its ions. The balanced equation for the dissociation is
(NH₄)₃PO₄ → 3NH₄⁺ + PO₄³⁻

The stoichiometric ratio between (NH₄)₃PO₄ and NH₄⁺ is 1 : 3

Hence, moles of (NH₄)₃PO₄ / moles of NH₄⁺ = 1 / 3
 
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Hence, moles of NH₄⁺ = moles of (NH₄)₃PO₄ x 3
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