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AnnyKZ [126]
3 years ago
9

Reaction is

Chemistry
1 answer:
-Dominant- [34]3 years ago
7 0
According  to the task, you  are proveded with patial pressure of CO2 and graphite, and here is complete solution for the task :
At first you have to find n1 =moles of CO2 and n2 which are moles of C 
<span>The you go :
</span>CO2(g) + C(s) \ \textless \ =\ \textgreater \  2CO(g)

n1 n2 0
-x -x +2x
n1-x n2-x 2x Kp=P^2 (CO)/Pco2
After that you have to use the formula PV=nRT
 Kp=(2x)^2/n1-x
Then you have to solve x, and for that you have to use <span>RT/V
And to find total values:</span>P(total)=n(total)*R*T/V
I am absolutely sure that this would be helpful for you.
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The partial pressure of methane in the mixture of methane and ethane has been 1 atm.

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The given methane has a partial pressure of 1 atm in the 15 L vessel. The addition of ethane results in the change in the total pressure of the mixture, as there have been additional moles of solute that contributes to the solution pressure.

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3 years ago
¡¡¡PLEASE HELP!!! I'm stuck on a question..
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 The half  life  of uranium- 238  is

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