Answer:
0.03g/mL
Explanation:
Given parameters include:
Five μL of a 10-to-1 dilution of a sample; This implies the Volume of dilute sample is given as 5 μL
Dilution factor = 10-to-1
The absorbance at 595 nm was 0.78
Mass of the diluted sample = 0.015 mg
We need to first determine the concentration of the diluted sample which is required in calculating the protein concentration of the original solution.
So, to determine the concentration of the diluted sample, we have:
concentration of diluted sample = 
= 
(where ∝ was use in place of μ in the expressed fraction)
= 0.003 mg/μL
The dilution of the sample is from 10-to-1 indicating that the original concentration is ten times higher; as such the protein concentration of the original solution can be calculated as:
protein concentration of the original solution = 10 × concentration of the diluted sample.
= 10 × 0.003 mg/μL
= 0.03 mg/μL
= 0.03g/mL
Hence, the protein concentration of the original solution is known to be 0.03g/mL
First off, we can find the volume that need to be filled:
2-1.25
=0.75L
Asbthe unit is still in Litres,we need to converge it to mL.
1L = 1000mL
mL needed:
=0.75×1000
=750mL
Therefore the answer is 750mL.
Hope it helps!
Answer:
Explanation:
F2 have the weakest attraction to each other because of higher electronegativity when they are brought close to each other they repel each other
Answer:
Both combustion and respiration involve the burning of the substrate. In both of these processes, the substance undergoes oxidation (in presence of oxygen).
...
Difference Between Respiration and Combustion.
Respiration Combustion
It takes place in a controlled manner inside the cells. It is an uncontrollable process.
Explanation:
An ether is a compound that has two functional groups separated by an oxygen. The typical structure appears like this: R - O - R', where R and R' are the functional groups. R and R' can only be alkyl and aryl groups. Take for example the simplest ether, Dimethyl ether. The formula is given as CH3OCH3, where there are two methyl groups on each side of the ether. Notice that CH3 is a methyl group, which is an alkyl group.
