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AlladinOne [14]
3 years ago
15

The substance on which the enzyme acts is called the _____ chemical.

Chemistry
1 answer:
Serga [27]3 years ago
8 0

Answer:

the answer is A

Explanation:

it is substrates because ,Enzymes are specialized proteins that catalyze or speed up chemical reactions within cells. The substance upon which an enzyme acts is called a substrate. Substrates are small molecules.

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Where are earthquakes and tsunamis more common and why?
Keith_Richards [23]
Tsunamis are the largest waves in the world. The edges of the plates, where earthquakes and volcanoes often occur, usually lie near the edges of the oceans
4 0
2 years ago
Read 2 more answers
You have 8 moles of a gas at 250 K in a 6 L container. What is the pressure of the gas? Show your work
Bogdan [553]

Hello:

In this case, we will use the Clapeyron equation:

P = ?

n = 8 moles

T = 250 K

R = 0.082 atm.L/mol.K

V = 6 L

Therefore:

P * V = n *  R * T

P * 6 = 8 * 0.082* 250

P* 6 = 164

P = 164 / 6

P = 27.33 atm


Hope that helps!

7 0
3 years ago
Help please ;( really don’t understand Chemistry would really appreciate it if can explain to me thank you!
Tanya [424]

Answer:

b)   O₂

d)   CH₄

Explanation:

In a chemical equation, the <u>reactants</u> are the substances that are written on the <u>left side</u>. The reactants react to produce the products. On the right side, the products are written.

The arrow => is used to separate the reactants from the products.

To the left of the arrow, you can see this written:

CH₄ + 2O₂

The plus sign + is used to separate each reactant.

In 2O₂ you can ignore the big 2 because it is a coefficient, which is written to balance the equation.

The reactants are CH₄ and O₂

7 0
3 years ago
What is the mass of a sample of a sample of iron (cp=0.44j/g•°C) when it is heated from 60°to 160°C. The heat is transferred is
scZoUnD [109]

Q=mcat

6600=(m)(.44)(100)

6600=(44m)

150= m

5 0
3 years ago
Two systems with heat capacities 19.9 J mol-1 K-1 and 28.2 ] mol 1 K-1 respectively interact thermally and come to an equilibriu
MAVERICK [17]

Answer : The initial temperature of system 2 is, 19.415^oC

Explanation :

In this problem we assumed that the total energy of the combined systems remains constant.

-q_1=q_2

m\times c_1\times (T_f-T_1)=-m\times c_2\times (T_f-T_2)

The mass remains same.

where,

C_1 = heat capacity of system 1 = 19.9 J/mole.K

C_2 = heat capacity of system 2 = 28.2 J/mole.K

T_f = final temperature of system = 30^oC=273+30=303K

T_1 = initial temperature of system 1 = 45^oC=273+45=318K

T_2 = initial temperature of system 2 = ?

Now put all the given values in the above formula, we get

-19.9J/mole.K\times (303-318)K=28.2J/mole.K\times (303-T_2)K

T_2=292.415K

T_2=292.415-273=19.415^oC

Therefore, the initial temperature of system 2 is, 19.415^oC

8 0
3 years ago
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