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levacccp [35]
3 years ago
5

Select the correct answer.

Chemistry
1 answer:
Sladkaya [172]3 years ago
5 0

Answer:

  • <u><em>Option D. There will be a shift toward the reactants.</em></u>

Explanation:

The reaction is:

       PCl_5(g)+heat\rightleftharpoons PCl_3(g)+Cl_2(g)

The application of LeChatelier's principle leads to consider the <em>heat</em> as a <em>reactant</em> or a product depending on if it is on the left side or the right side.

In this reaction, the <em>heat</em> is on the left side, thus it must be considered a <em>reactant</em>.

Decreasing the temperature is equivalent to remove or consume heat. Thus, the reaction must shif to the left to compensate that reduction of heat. That is the reverse reaction shall be favored.

In conclusion, <em>there will be a shift toward the reactants.</em>

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In this experiment you will create solutions with different ratios of ethanol and water. What is the mole fraction of ethanol wh
Andrej [43]

Answer:

The mole fraction of ethanol is 0.6. A 10 mL volumetric pipette must be used for to measure the 10 mL of ethanol. The vessel should be clean and purged.

Explanation:

For calculating mole fraction of ethanol, the amount of moles ethanol must be calculated. Using ethanol density (0.778 g/mL), 10 mL of ethanol equals to 7.89 g of ethanol and in turn 0.17 moles of ethanol. The same way for calculate the amount of water moles (ethanol density=0.997 g/mL). 2 mL of water correspond to 0.11. The total moles are: 0.17+0.11=0.28. Mole fraction alcohol is: 0.17/0.28=0.6

5 0
3 years ago
A mixture of NH3 and N2H4 is placed in a sealed container at 300K. The total pressure is 0.50 atm. The container is heated to 12
kiruha [24]

Answer:

The percent of N2H4 in the original mixture is 25 %

Explanation:

Step 1: Data given

Temperature in the sealed container = 300K

The total pressure = 0.50 atm

The container is heated to 1200K

The total pressure at 1200K = 4.5 atm

Step 2: The balanced equation

2NH3 → N2 + 3H2

N2H4 → N2 + 2H2

Step 3: Calculate the initial moles

p*V = n*R*T

⇒ with p = the total pressure = 0.50 atm

⇒ with V = the volume of the gas

⇒ with n = the total moles of the gasses (n1 + n2)

⇒ with R = the gas constant =  0.08206 L*atm/mol*K

⇒ with T = the temperature in the container =  300

0.50*V= (n1+n2)*R*300

Step 4:  after decmposition,

from 2 moles of NH3 we'll get 4 moles  (n1 → 2n1)

from 1 moles of N2H4 we'll get 3 moles. (n2 → 3n2)

The total moles for mixture = 2n1 + 3n2

p*V= n*R*T

⇒ with p = the total pressure at 1200 K = 4.5 atm

⇒ V = The volume

⇒ with n = the number of moles

⇒ with R = the gas constant = 0.08206 L* atm/ K*mol

⇒ with T = the temperature = 1200 K

4.5*V = (2n1 + 3n2)*R*1200

0.50*V= (n1+n2)*R*300

Step 5: Calculate the percentage of N2H4

After dividing both equations we get:

n2/(n1+n2) = 1/4

n1 = 3 and n2 = 1

Percentage of N2H4 therfore is => 1*100/4 = 25%

and % of  NH3 => 75%

The percent of N2H4 in the original mixture is 25 %

4 0
4 years ago
Ammonium carbonate and iron(iii) nitrate are combined, solid iron(iii) carbonate and a solution of ammonium nitrate are formed.
Vanyuwa [196]

Answer:

The net ionic equation is: 3CO₃²⁻(aq) + 2Fe³⁺(aq) → Fe₂(CO₃)₃(s).

Explanation:

  • For the mentioned reaction:
  • We have the Molecular reaction:

3(NH₄)₂CO₃(aq) + 2Fe(NO₃)₃(aq) → Fe₂(CO₃)₃(s) + 6NH₄NO₃(aq)

 

  • We have the total ionic reaction:

6NH₄⁺(aq) + 3CO₃²⁻(aq) + 2Fe³⁺(aq) + 6NO₃⁻ → Fe₂(CO₃)₃(s) + 6NH₄⁺(aq) + 6NO₃⁻(aq).

<em>NH₄⁺(aq) and NO₃⁻(aq) are spectator ions that are not changed through the reaction and still dissolved in the medium, so they can be omitted to get the net ionic equation.</em>

<em />

  • So, the net ionic equation is:

<em>3CO₃²⁻(aq) + 2Fe³⁺(aq) → Fe₂(CO₃)₃(s).</em>

6 0
3 years ago
Phosphate, PO43−, is a polyatomic ion that can combine with any cation to form an ionic compound.
vesna_86 [32]

Answer:

Li3PO4 - correct

FePO4 - correct

Cu3PO4 - correct

Mg3(PO4)2 - correct

Explanation:

In order to answer this question we must be conversant with the idea of valency as well as the idea of writing formula of ionic substances.

Lithium has a valency of 1 while PO4^3- has a valency of 3 so the correct formula of lithium phosphate must be Li3PO4 after the exchange of valencies.

Iron III has a valency of 3 while the phosphate ion also has a valency of 3 so the subscripts cancel out and iron III phosphate is FePO4.

Copper I ion has a valency of 1 and the phosphate ion has a valency of 3. When they exchange valencies, the formula of the compound is Cu3PO4.

Magnesium has a valency of 2 while the phosphate ion has a valency of 3. The exchange of valency gives us the formula Mg3(PO4)2.

7 0
3 years ago
The "fatal flaw" in Rutherford's model of the atom, which was corrected by Bohr's model, was the idea that, if the electrons wer
Gennadij [26K]

The answer is

A. orbiting the nucleus, changing direction and thus giving off energy, the electrons would lose all energy and collapse into the nucleus.

Bohr stated that electron can be only on certain distances from nucleus. Electrons can be only on allowed orbits.

7 0
4 years ago
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