Answer:
d) V = 91.3 L
Explanation:
Given data:
Volume of nitrogen = ?
Temperature = standard = 273.15 K
Pressure = standard = 1 atm
Number of atoms of nitrogen = 2.454×10²⁴ atoms
Solution:
First of all we will calculate the number of moles of nitrogen by using Avogadro number.
1 mole = 6.022×10²³ atoms
2.454×10²⁴ atoms × 1 mol / 6.022×10²³ atoms
0.407×10¹ mol
4.07 mol
Volume of nitrogen:
PV = nRT
1 atm × V = 4.07 mol ×0.0821 atm.L /mol.K ×273.15 K
V = 91.3 atm.L /1 atm
V = 91.3 L
Input the atomic masses of Mg and P to give 134.84g/mol
Explanation:
The molar mass of a substance (atom or molecule or compound) is the mass in grams of one mole of the substance:
When dealing with an element the molar mass is the relative atomic mass expressed as g/mol.
For compounds, you add the atomic masses of the component atoms and you sum up.
You simply input the atomic mass of 3 atoms of Mg and 2 atoms of P
Atomic mass of Mg = 24.3g/mol
P = 30.97g/mole
Molar mass of Mg₃P₂ = 3(24.3) + 2(30.97) = 134.84g/mol
learn more:
Molar mass brainly.com/question/2861244
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