Question

An ac voltage, whose peak value is 250 V , is across a 330-Ω resistor. Part A What is the peak current in the resistor?

Answer 1

Answer:

Peak current is 0.75 A

RMS voltage is 176.77 V

RMS current is 0.53 A

Explanation:

Peak current is

$I=\frac{V}{R} \\\\I=\frac{250}{330}\\I=0.75 A$

RMS voltage is

$V_{RMS}=\frac{V}{\sqrt{2} } \\V_{RMS}=\frac{250}{\sqrt{2} }\\V_{RMS}=176.77 V$

RMS current is

$I_{RMS}=\frac{V_{RMS}}{R} \\I_{RMS}=\frac{176.77}{330} \\I_{RMS}=0.53 A$