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Natali5045456 [20]
3 years ago
8

A group of tourists drives through a state park in Maine. While arguing about whether the animal they've just seen is an Elk or

a Moose, a chipmunk darts across the park road. The driver, who was traveling 6.7 m/s through the park slams on their breaks and comes to a stop. If the car has an acceleration of -8.3 m/s2, how long does it take the car to stop?
Physics
1 answer:
podryga [215]3 years ago
6 0

Answer:

0.8 second

Explanation:

Given data

Speed v=6.7m/s

Deceleration = - 8.3m/s²

Initial velocity u= 0m/s

We can solve for the distance covered upon breaking the speed using the expression

v=u +at

6.7=0-(8.3)t

6.7=8.3t

Divide both sides by 8.3

6.7/8.3=t

t=6.7/8.3

t=0.8 second

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The correct explanation for the process of formation of dew from the water vapour is The water releases energy which causes the water molecules to have less kinetic and potential energy, changing their configuration from gas to liquid.

vapour is a gaseous form, while dew is a liquid state of matter therefore it's clear that vapour has to release energy to come in the liquid state, and in this process vapour, water molecules lose their kinetic and potential energy.

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a fixed amount of ideal gas is held in a rigid container that expands negligibly when heated. at 20 the gas pressure is p. if we
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Answer:

When the temperature of the gas is increased from 20 to 40, the pressure will be 2p

Explanation:

Given;

initial temperature of the gas, T₁ = 20 K

final temperature of the gas, T₂ = 40 k

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final pressure of the gas, P₂ = ?

Apply pressure law of gases;

\frac{P_1}{T_1} = \frac{P_2}{T_2} \\\\P_2 = \frac{P_1T_2}{T_1} \\\\P_2 = \frac{40P}{20} \\\\P_2 = 2P

Therefore, when the temperature of the gas is increased from 20 to 40, the pressure will be 2p

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How is a wave created?
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Explanation:

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A 3.00-kg crate slides down a ramp. the ramp is 1.00 m in length and inclined at an angle of 30.08 as shown in the figure. The c
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Answer:

2.55 m/s

Explanation:

A 3.00-kg crate slides down a ramp. the ramp is 1.00 m in length and inclined at an angle of 30° as shown in the figure. The crate starts from rest at the top, experiences a constant friction force of magnitude 5.00 N, and continues to move a short distance on the horizontal floor after it leaves the ramp. Use energy methods to determine the speed of the crate at the bottom of the ramp.

Solution:

The work done by friction is given as:

W_f=F_f\Delta S\\\\Where\ F_f\ is\ the \ frictional\ force=-5N(the\ negative \ sign\ because\ it\\acts\ opposite\ to \ direction\ of\ motion),\Delta S=slope\ length=1\ m\\\\W_f=F_f\Delta S=-5\ N*1\ m=-5J

The work done by gravity is:

W_g=F_g*s*cos(\theta)\\\\F_g=force\ due\ to\ gravity=mass*acceleration\ due\ to\ gravity=3\ kg*9.81\\m/s^2, s=1\ m, \theta=angle\ between\ force\ and\ displacement=90-30=60^o\\\\W_g=3\ kg*9.81\ m/s^2*1\ m*cos(60)=14.72\ J\\\\The\ Kinetic\ energy(KE)=W_f+W_g=14.72\ J-5\ J=9.72\ J\\\\Also, KE=\frac{1}{2} mv^2\\\\9.72=\frac{1}{2} (3)v^2\\\\v=\sqrt{\frac{2*9.72}{3} } =2.55\ m/s

4 0
3 years ago
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