Let us start from considering monochromatic light as an incidence on the film of a thickness t whose material has an index of refraction n determined by their respective properties.
From this point of view part of the light will be reflated and the other will be transmitted to the thin film. That additional distance traveled by the ray that was reflected from the bottom will be twice the thickness of the thin film at the point where the light strikes. Therefore, this relation of phase differences and additional distance can be expressed mathematically as
![2t + \frac{1}{2} \lambda_{film} = (m+\frac{1}{2})\lambda_{film}](https://tex.z-dn.net/?f=2t%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%5Clambda_%7Bfilm%7D%20%3D%20%28m%2B%5Cfrac%7B1%7D%7B2%7D%29%5Clambda_%7Bfilm%7D)
We are given the second smallest nonzero thickness at which destructive interference occurs.
This corresponds to, m = 2, therefore
![2t = 2\lambda_{film}](https://tex.z-dn.net/?f=2t%20%3D%202%5Clambda_%7Bfilm%7D)
![t = \lambda_{film}](https://tex.z-dn.net/?f=t%20%3D%20%5Clambda_%7Bfilm%7D)
The index of refraction of soap is given, then
![\lambda_{film} = \frac{\lambda_{vacuum}}{n}](https://tex.z-dn.net/?f=%5Clambda_%7Bfilm%7D%20%3D%20%5Cfrac%7B%5Clambda_%7Bvacuum%7D%7D%7Bn%7D)
Combining the results of all steps we get
![t = \frac{\lambda_{vacuum}}{n}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B%5Clambda_%7Bvacuum%7D%7D%7Bn%7D)
Rearranging, we find
![\lambda_{vacuum} = tn](https://tex.z-dn.net/?f=%5Clambda_%7Bvacuum%7D%20%3D%20tn)
![\lambda_{vacuum} = (278)(1.33)](https://tex.z-dn.net/?f=%5Clambda_%7Bvacuum%7D%20%3D%20%28278%29%281.33%29)
![\lambda_{vacuum} = 369.74nm](https://tex.z-dn.net/?f=%5Clambda_%7Bvacuum%7D%20%3D%20369.74nm)
The correct answer is: Option (A) 75 J
Explanation:
First, be careful with the units here. As you can see it is mentioned that there is a 50N box. It means that the weight (<em>mg</em>) of the box is given as the unit is <em>Newton</em>, not its mass (which is in kg).
As,
Potential-energy = mass * acceleration-due-to-gravity * height
PE = m*g*h --- (A)
In equation (A), mg is actually the weight of the box, which is given.
mg = 50N
h = height = 1.5m
Plug the values in equation (A):
PE = 50 * 1.5 = <em>75 J (Option A)</em>
The x -component of the object's acceleration is 2 m/s².
<h3>What's the resultant force along x- direction?</h3>
- Forces along x axis direction are as follows
- 4N along +x axis, so it's taken as +4 N
- 2N along -x axis , so it's taken as -2N.
- Resultant force along x direction = 4N - 2N = 2 N which is along + ve x direction.
<h3>What's the acceleration along x axis direction?</h3>
- As per Newton's second law, Force = mass × acceleration of the object
- Force along x axis= mass × acceleration along x axis= 2N
- Acceleration = 2/ mass = 2/1 = 2 m/s²
Thus, we can conclude that the acceleration along x axis is 2 m/s².
Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: The forces in (Figure 1) are acting on a 1.0 kg object. What is ax, the x-component of the object's acceleration?
Learn more about the acceleration here:
brainly.com/question/460763
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Humid air has higher pressure because of the heaviness of the water
On Earth, a cannonball with a mass of 20 kg would weigh 196 Newtons.
With the formula F=mg, where F is the weight in Newtons, m is the mass, and g is the acceleration due to gravity on the Earth which is 9.8m/s^2.
F=20kg x 9.8m/s^2= 196 Newtons
BUT on the moon, acceleration due to gravity is 1.6 m/s^2,
so F=mg=20kgx1.6m/s^2= 32 N