PLS URGENT!!

A 250 - ω resistor is connected in series with a 4.80 - μf capacitor. the voltage across the capacitor is vc=(7.60v)⋅sin[(120rad

galben [10]

<span>553 ohms The Capacitive reactance of a capacitor is dependent upon the frequency. The lower the frequency, the higher the reactance, the higher the frequency, the lower the reactance. The equation is Xc = 1/(2*pi*f*C) where Xc = Reactance in ohms pi = 3.1415926535..... f = frequency in hertz. C = capacitance in farads. I'm assuming that the voltage and resistor mentioned in the question are for later parts that are not mentioned in this question. Reason is that they have no effect on the reactance, but would have an effect if a question about current draw is made in a later part. With that said, let's calculate the reactance. The 120 rad/s frequency is better known as 60 Hz. Substitute known values into the formula. Xc = 1/(2*pi* 60 * 0.00000480) Xc = 1/0.001809557 Xc = 552.6213302 Rounding to 3 significant figures gives 553 ohms.</span>

6 0

4 years ago

Read 2 more answers

La) What is meant by the term Basic Quantities.

castortr0y [4]

Answer:

A basic quantity is basically the physical quantity that can not be defined in terms of other quantities.

Explanation:

A basic quantity is basically the physical quantity that can not be defined in terms of other quantities.

Some of the names of the basic quantities include:

Mass, denoted by the symbol 'm', with S.I. unit 'kg'
Length, denoted by symbol 'l', with S.I. unit 'm'
Time, denoted by symbol 't', with S.I. unit 's'
Current, denoted by 'I', with S.I. unit 's' 'A'
Temperature, denoted by 'T', with S.I. unit 'K'
Amount of substance, denoted by 'n', with S.I. unit 'mol'
Luminous Intensity, denoted by 'Iv', with S.I. unit 'cd'

A basic quantity is chosen arbitrarily.

5 0

3 years ago

A sample of ore containing radioactive strontium 38Sr90 has an activity of 8.2 × 105 Bq. The atomic mass of strontium is 89.908

ahrayia [7]

From the activity values and the decay constant, the mass of of Strontium in the sample is:

$1.62 × 10^{-7}g$

<h3>What is the decay constant of an element?</h3>

The decay constant of an element is the probability of decay of a nucleus per unit time.

{λ = ln 2 / t1/2

where;

t1/2 is the half-life of the isotope.

The half-life is converted to seconds since the decay constant is asked in per seconds.

$28.8 years = 28.8 × 3.156 × 10^{7} = 908928000 s \\$

Hence;

$λ = \frac{ln2}{90892800s} = 7.626 s^{-1}$

The activity of the element, A, the decay constant, λ and the number of nuclei, N are related as follows:

A = (–) λN

$N = \frac{8.25 ×10^{5}}{7.626×10^{-10}} = 1.082 × 10^{15}$

Molar mass of Strontium-90 is 90 g.

1 mole of Strontium-90 contains 6.02×10^23 nuclei.

The mass, m of Strontium in the sample is calculated:

$m = 1.082 × 10^{15} × \frac{90 g}{6.02 × 10^{23}} = 1.62 × 10^{-7}g \\$

Therefore, the mass of of Strontium in the sample is:

$1.62 × 10^{-7} \: g$

Learn more about decay constant at: brainly.com/question/17159453

5 0

3 years ago

Resistance to the motion of an automobile consists of road friction, which is almost independent of speed, and air drag, which i

Troyanec [42]

Answer:

73.52983 Hp

Explanation:

m = Mass of car = $\dfrac{W}{g}$

W = Weight of car = 12000 N

a = Acceleration = 0.96 m/s²

Velocity of the car

$v=82\times \dfrac{1000}{3600}\\\Rightarrow v=\dfrac{82}{3.6}\\\Rightarrow v=\dfrac{41}{1.8}$

From the question

$F=300+1.8v^2\\\Rightarrow F=300+1.8\times \left(\dfrac{41}{1.8}\right)^2\\\Rightarrow F=1233.88\ N$

Balancing the forces

$\dfrac{P}{v}-1233.88=ma\\\Rightarrow P=(ma+12000)v\\\Rightarrow P=\left(\dfrac{12000}{9.81}\times 0.96+1233.88\right)\dfrac{41}{1.8}\\\Rightarrow P=54853.26055\ W=\dfrac{54853.26055}{746}\\\Rightarrow P=73.52983\ Hp$

The power is 73.52983 Hp

6 0

3 years ago

The chart shows the masses of selected particles.

Molodets [167]

Answer: 0.2 u

Explanation:

The atomic mass of nuclide is written as a superscript. On the left (reactants) aide of the nuclear equation shown, the total atomic mass is 235.0 + 1.0 u = 236 u. On the right (products) side reaction, the total atomic mass is 137.9u + 94.9u + 3 x 1.0u = 235.8 u. Therefore, 0.2 mass units must have been converted into energy.

6 0

3 years ago