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3 years ago

How is light energy different from both sound and heat energy?

Physics

1 answer:

Xelga [282]3 years ago

6 0

Answer:

Light is energy that travels in waves and is produced by hot, energetic objects, while sound and heat energy are created with vibration and radiation, convection, or conduction.

Explanation:

Light bulbs are hot, energetic objects. You know the light bulb needs energy because you have to turn the light switch on to provide electricity for it. The electricity flows through either a thin metal wire or a gas. The wire or gas glows and gives off light when heated.

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If the amplitude of a wave is 4 feet, what is the Wave Height?

Alexus [3.1K]

A wave is a disturbance that moves along a medium from one end to the other. If one watches an ocean wave moving along the medium (the ocean water), one can observe that the crest of the wave is moving from one location to another over a given interval of time. The crest is observed to cover distance. The speed of an object refers to how fast an object is moving and is usually expressed as the distance traveled per time of travel. In the case of a wave, the speed is the distance traveled by a given point on the wave (such as a crest) in a given interval of time. In equation form,

5 0

3 years ago

Read 2 more answers

In Millikan's experiment, an oil drop of radius 1.362 μm and density 0.888 g/cm3 is suspended in chamber C when a downward-point

Misha Larkins [42]

Answer:

The charge on the oil drop is 3e

Explanation:

F = qE

Where;

F is the applied force in Newton

E is the electric field potential N/C

q is charge in C

Given;

Radius, r = 1.362 μm = 1.362 X 10⁻⁶ m

density, ρ = 0.888 g/cm³ = 0.888 X 10³ kg/m³

Electric field potential = 1.92 ✕ 10⁵ N/C

F =mg

mass of the oil drop = density, ρ X volume of the oil drop

volume of the oil drop (spherical) = (4/3)πr³ = 1.3333π(1.362 X 10⁻⁶)³

⇒ volume of the oil drop = 10.584 X 10⁻¹⁸ m³

mass of the oil drop = 0.888 X 10³ (kg/m³) X 10.584 X 10⁻¹⁸ (m³)

⇒ mass of the oil drop = 9.399 X 10⁻¹⁵ kg

⇒ F =mg = 9.399 X 10⁻¹⁵ kg X 9.8 = 9.21 X10⁻¹⁴ N

F = qE

q = F/E

q = (9.21 X10⁻¹⁴)/(1.92 ✕ 10⁵) = 4.797 X 10⁻¹⁹ C

In terms of e

1e = 1.6 X10⁻¹⁹ C

= (4.797 X 10⁻¹⁹ C)/(1.6 X10⁻¹⁹ C) = 3e

Therefore, the charge on the oil drop is 3e

7 0

3 years ago

Question 1 of 10

ivanzaharov [21]

The answer would be 46.482 because you multiply 18.3 by 2.54 because for every inch you get 2.54 centimeters

6 0

2 years ago

Read 2 more answers

Encuentra la masa molar<br><br> TO<br><br> de 65 litros de SO2

shepuryov [24]

La masa molar de 65 litros de SO2 es igual a 64,1 g/mol.

<h3>Masa molar</h3>

La masa molar de un compuesto depende de su masa presente en 1 mol, entonces:

$MM=\frac{m}{mol}$

Para calcular la masa molar de un compuesto, simplemente suma las masas de cada elemento en el compuesto, así:

$MM_O = 16g/mol\\MM_S= 32.1g/mol$

$32.1 + 2\times 16 = 64.1g/mol$

Así, la masa molar de 65 litros de SO2 es igual a 64,1 g/mol.

Obtenga más información sobre la masa molar en: brainly.com/question/17109809

8 0

3 years ago

At its Ames Research Center, NASA uses its large "20-G" centrifuge to test the effects of very large accelerations ("hypergravit

Over [174]

Answer:

v=32.9m/s

Explanation:

The acceleration needed to mantain a circular motion of radius r and speed v is given by the equation $a=v^2/r$

This is the centripetal acceleration. The person will feel what is called a centrifugal acceleration, of the same value, because he is not in an inertial frame (thus subject to fictitious forces, product of inertia).

We want to know the speed of his head when it is subject to 12.5 times the value of the acceleration of gravity while moving on a 8.84m radius circle, so we must do:

$v=\sqrt{ar} = \sqrt{12.5gr}=\sqrt{(12.5)(9.8m/s)(8.84m)}=32.9m/s$

7 0

3 years ago