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dusya [7]
3 years ago
14

Changing your toilet can reduce water pollution because _______.

Physics
2 answers:
velikii [3]3 years ago
8 0
More efficient plumbing uses less water and creates smaller volume of waste is the answer why changing your toilet can reduce water pollution. If there is a problem in your toilet, you will use more water. The more water you pour, the more water pollution is added.
777dan777 [17]3 years ago
5 0

Answer:D

Explanation:

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Does air defy gravity?
Andreyy89

Answer:

If you were to inject air into space what would have happen?

Explanation:

In order for air to defy gravity, it would require atmospheric pressure. But air dosen't defy gravity unless it has the support of atmospheric pressure.

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3 years ago
Question 1 of 10
kirill115 [55]

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4 0
3 years ago
Each of 100 identical blocks sitting on a frictionless surface is connected to the next block by a massless string. The first bl
o-na [289]

Answer:

The tension in the string connecting block 50 to block 51 is 50 N.

Explanation:

Given that,

Number of block = 100

Force = 100 N

let m be the mass of each block.

We need to calculate the net force acting on the 100th block

Using second law of newton

F=ma

100=100m\times a

ma=1\ N

We need to calculate the tension in the string between blocks 99 and 100

Using formula of force

F_{100-99}=ma

F_{100-99}=1

We need to calculate the total number of masses attached to the string

Using formula for mass

m'=(100-50)m

m'=50m

We need to calculate the tension in the string connecting block 50 to block 51

Using formula of tension

F_{50}=m'a

Put the value into the formula

F_{50}=50m\times a

F_{50}=50\times1

F_{50}=50\ N

Hence, The tension in the string connecting block 50 to block 51 is 50 N.

8 0
3 years ago
Which type of electromagnetic waves has highest frequency​
vesna_86 [32]

Answer:

Gamma rays have the highest energies.

Explanation:

HOPE IT WILL HELP ^_^

6 0
3 years ago
Read 2 more answers
A charge of 25 nC is uniformly distributed along a straight rod of length 3.0 m that is bent into a circular arc with a radius o
Greeley [361]

Answer:

E = 31.329 N/C.

Explanation:

The differential electric field dE at the center of curvature of the arc is

dE = k\dfrac{dQ}{r^2}cos(\theta ) <em>(we have a cosine because vertical components cancel, leaving only horizontal cosine components of E. )</em>

where r is the radius of curvature.

Now

dQ = \lambda rd\theta,

where \lambda is the charge per unit length, and it has the value

\lambda = \dfrac{25*10^{-9}C}{3.0m} = 8.3*10^{-9}C/m.

Thus, the electric field at the center of the curvature of the arc is:

E = \int_{\theta_1}^{\theta_2} k\dfrac{\lambda rd\theta  }{r^2} cos(\theta)

E = \dfrac{\lambda k}{r} \int_{\theta_1}^{\theta_2}cos(\theta) d\theta.

Now, we find \theta_1 and \theta_2. To do this we ask ourselves what fraction is the arc length  3.0 of the circumference of the circle:

fraction = \dfrac{3.0m}{2\pi (2.3m)}  = 0.2076

and this is  

0.2076*2\pi =1.304 radians.

Therefore,

E = \dfrac{\lambda k}{r} \int_{\theta_1}^{\theta_2} cos(\theta)d\theta= \dfrac{\lambda k}{r} \int_{0}^{1.304}cos(\theta) d\theta.

evaluating the integral, and putting in the numerical values  we get:

E = \dfrac{8.3*10^{-9} *9*10^9}{2.3} *(sin(1.304)-sin(0))\\

\boxed{ E = 31.329N/C.}

4 0
3 years ago
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