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alexandr1967 [171]
3 years ago
7

Refer to Concept Simulation 4.4 for background relating to this problem. The drawing shows a large cube (mass = 28.9 kg) being a

ccelerated across a horizontal frictionless surface by a horizontal force P. A small cube (mass = 4.4 kg) is in contact with the front surface of the large cube and will slide downward unless P is sufficiently large. The coefficient of static friction between the cubes is 0.710. What is the smallest magnitude that P can have in order to keep the small cube from sliding downward?
Physics
1 answer:
Usimov [2.4K]3 years ago
6 0

Answer:

smallest magnitud is P=33.3 N

Explanation:

We are analyze the situation as an external force is applied and there is a friction force. We have a problem with Newton's second law.

          F = ma

As the two blocks go together they must have the same acceleration, so we can calculate this for the entire system

        P = (m1 + m2) a

        a = P / (m1 + m2)

In this case there is no friction force because the small block does not touch the ground.

In order to calculate the friction force, we must analyze each system component separately.

The large block on the X axis has an applied P force and as it moves feels a force from the small block.  In the Y axis has the weight (W1) and the reaction to normal (N1)

For the small block on the X axis, the force it feels is the thrust of the large block, note that this is an action and reaction force between the two blocks, it is the same definition we have of the normal one, so we can call this force (N)

Y axis it has the weight (W2) down, the force of friction (fr) that opposes the movement, so it is directed upwards. we write these equations

       N = m2 a

       fr -W2 = 0    

       fr = W2

       

The definition of friction force is

       fr = μ N

       

Let's replace and calculate

       μ (m2 a) = m2 g

       μ (P / (m1 + m2)) = g

       P = g /μ  (m1 + m2)

Let's calculate the value of this force

       P = 9.8 / 0.710 (28.9 +4.4)

       P = 13.80 (33.3)

       P = 33.3 N

This is the minimum friction force that prevents the block from sliding down

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Answer:

b.A single force acts on the object.

Explanation:

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So it is correct to say that an object with constant velocity has no forces acting on it.

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So (a), (c) and (d) are correct because of what was previously discussed.

<u>Note that b cannot be true since it violates Newton's first law, since the object is moving at a constant velocity. </u>

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3 years ago
As outlaws escape in their getaway ear, which goes 3/4 c, the police officer fires a bullet from a pursuit ear, which only goes
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Answer:

a) Bullet will hit

b) Bullets will not hit

Explanation:

Given:

The velocity of the bullet, u = \frac{1}{3}c in the rest frame of the bullet pursuit car

The velocity of the original frame of reference, v = -\frac{1}{2}c with respect to the pursuit car.

Now, according to the Galileo

the velocity of the bullet in the original frame of reference (u') will be

u' = u - v

on substituting the values we get

u' = \frac{1}{3}c-(-\frac{1}{2}c)

or

u' = \frac{1}{3}c+\frac{1}{2}c

or

u' = \frac{5}{6}c

since this velocity ( \frac{5}{6}c) is greater than the ( \frac{3}{4}c)

hence,

<u>the bullet will hit</u>

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the velocity of the bullet in the original frame of reference (u') will be

u'=\frac{u-v}{1-\frac{uv}{c^2}}

on substituting the values we get

u'=\frac{\frac{1}{3}c-\frac{1}{2}c}{1-\frac{\frac{1}{3}c\times \frac{1}{2}c}{c^2}}

or

u'=\frac{\frac{5}{6}c}{1-\frac{1}{6}}

or

u'=\frac{5}{7}c

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7 0
4 years ago
A lamp has a power of 120 w and is left on for 24 hours. A television has a power of 350 W and is left on for 3 hours. Which sta
soldi70 [24.7K]
<h2>Hello!</h2>

The answer is C. The television uses 6,588,000 J less than the lamp.

<h2>Why?</h2>

First, we must know that 1 Wh( Watt consumed in 1 hour) = 3600 J

Wh is the unit that express the energy amount of consumed in 60 minutes/ 1 hour.

So,

From the enunciate information we can calculate the energy consumed by the lamp and the television.

For the lamp, we have that it left on for 24 hours and it has a power of 120

For the television, we have that it left on for 3 hours and it has a power of 350W

Calculating the energy consumed (Wh) we have:

Wh= Watt*Time= 120 Watt* 24 hours= 2880 Wh

and converting it to Joule, we have:

2880 Wh*\frac{3600 J}{1 Wh}= 10,368,000 J

Doing the same for the television, we have:

Wh= 350 Watt* 3 hours= 1050 Wh

and converting it to Joule, we have:

1050 Wh*\frac{3600 J}{1 Wh}= 3,780,000 J

Finally, we have

10,368,000J(Lamp)-3,780,000J(Television)= 6,588,000J:

Then having calculated both consume, we have that the television uses 6,588,000 J less than the lamp.

3 0
3 years ago
Read 2 more answers
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