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3 years ago

What are objects that are less dense than water

Physics

1 answer:

GaryK [48]3 years ago

7 0

Answer:

Apples, empty bottles, balloons, etc.

Explanation:

The air is the cause of why these object are less dense than water.

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The angular velocity of a 755-g wheel 15.0 cm in diameter is given by the equation ω(t) = (2.00 rad/s2)t + (1.00 rad/s4)t 3. (a)

Lunna [17]

Answer:

The number of radians turned by the wheel in 2s is $\theta= 8\ radians$

The angular acceleration is $\alpha =14 rad/s^2$

Explanation:

The angular velocity is given as

$w(t) = (2.00 \ rda/s^2)t + (1.00 rad /s^4)t^3$

Now generally the integral of angular velocity gives angular displacement

So integrating the equation of angular velocity through the limit 0 to 2 will gives us the angular displacement for 2 sec

This is mathematically evaluated as

$\theta(t ) = \int\limits^2_0 {2t + t^3} \, dt$

$= [\frac{2t^2}{2} + \frac{t^4}{4}] \left\{ 2} \atop {0}} \right.$

$= [\frac{2(2^2)}{2} + \frac{2^4}{4}] - 0$

$= 4 +4$

$\theta= 8\ radians$

Now generally the derivative of angular velocity gives angular acceleration

So the value of the derivative of angular velocity equation at t= 2 gives us the angular acceleration

This is mathematically evaluated as

$\frac{dw}{dt} = \alpha (t) = 2 + 3t^2$

so at t=2

$\alpha (2) = 2 +3(2)^2$

$\alpha =14 rad/s^2$

7 0

2 years ago

According to Archimedes’ principle, the mass of a floating object equals the mass of the fluid displaced by the object. Use this

Andrew [12]

Answer:

Part a)

$\rho = 0.55 g/cm^3$

Part b)

$\rho_L = 1.49 g/cm^3$

Part c)

Since we know that the base area will remain same always

so here the length and width of the object is not necessary to obtain the above data in such type of questions

Explanation:

Part a)

As we know that when cylinder float in the water then weight of the cylinder is counter balanced by the buoyancy force

So here we know

buoyancy force is given as

$F_b = \rho_w V_{sub} g$

$F_b = (1 g/cm^3) (30 - 13.5) Ag$

$F_b = 16.5 Ag$

Now we know that the weight of the cylinder is given as

$W = \rho (30 cm)A g$

now we have

$\rho (30 cm) A g = 16.5 A g$

$\rho = 0.55 g/cm^3$

Part b)

When the same cylinder is floating in other liquid then we will have

$F_b = \rho_L (30 - 18.9 )A g$

so we have

$\rho_L (11.1) Ag = 0.55(30) Ag$

$\rho_L = 1.49 g/cm^3$

Part c)

Since we know that the base area will remain same always

so here the length and width of the object is not necessary to obtain the above data in such type of questions

3 0

2 years ago

For an object to orbit another object

STatiana [176]

B. Inertia and gravity must be balanced.

8 0

3 years ago

Which of the following situations has more kinetic energy than potential energy?

MrMuchimi

Answer:

C. a rolling bowling ball

I just answered this question on my quiz.

3 0

2 years ago

A spring gun is made by compressing a spring in a tube and then latching the spring at the compressed position. A 4.87-g pellet

Serga [27]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The work done by the spring is = $0.27 J$

Explanation:

Force = torque × length

Given

F = 9.13 N

length (L) = 5.91 cm = 0.0591 m [Note 1 m = 100 cm ]

considering the formula above

$9.13 = k * 0.0591$ where k denotes torque

$k = 154.48\ N/m$

Energy Stored $= \frac{1}{2} k x^2$

$= \frac{1}{2} * 154.48 * (0.0591)^2$

$= 0.27J$

8 0

3 years ago