The amount of heat needed to increase the temperature of a 1-kilogram substance by 1°C is known as the specific heat of the substance.
the formula for specific heat of a substance is given as
c = Q/(m ΔT)
where Q = Heat required to change the temperature by 1°C
m = mass of the substance
ΔT = change in temperature.
the units of specific heat is given as Joules/(kilogram °C)
<span>Total KE = KE (rotational) + KE (translational)
Moment of inertia of sphere is I = (2/5)mr^2
So KE (rotational) = (1/2) x I x w^2 = (1/2) x (2/5)mr^2 x w^2 = (1/5) x m x r^2 x w^2
KE (translational) = (1/2) x m x v^2 = (1/2) x m x (rw)^2 = (1/2) x m x r^2 x w^2
Hence KE = (1/5) x m x r^2 x w^2 + (1/2) x m x r^2 x w^2 = m x r^2 x w^2 ((1/5) + (1/2))
KE = (7/10) m x r^2 x w^2
Calculating the fraction of rotational kinetic energy to total kinetic energy,
= rotational kinetic energy / total kinetic energy
= (1/5) x m x r^2 x w^2 / (7/10) m x r^2 x w^2 = (1/5) / (7/10) = 2 / 7
The answer is 2 / 7</span>
Answer:
3.6 m/s
Explanation:
From the law of conservation of momentum,
Total momentum before jump = Total momentum after jump
<em>Note: Before Dan jump off the skateboard, they where both moving with the same velocity</em>
u(m+m') = mv+m'v'................. Equation 1
Where m = Dan's mass, m' = mass of the skateboard, u = common velocity before the jump, v = Dan's final velocity, v' = The final velocity of the skateboard.
make v the subject of the equation
v = [u(m+m')-m'v')]/m.............. Equation 2
Given: u = 4.0 m/s, m = 50 kg, m' = 5 kg, v' = 8 m/s
Substitute into equation 2
v = [4(50+5)-(5×8)]/50
v = (220-40)/50
v = 180/50
v = 3.6 m/s
Answer:
Both technicians A and B are correct, the information on how to fill the car tires can be located on the tire and on the placard on the driver's door jam
Explanation:
The instruction on proper inflation of car tires can be found on the tire information placard in the door jam area or the fuel filler door, in the glove box or in the car or tire manual
The tire information of the proper pressure to fill the tires is also visibly engraved on the sides of the car tire, where other information such as the requirement for training on tire filling/changing, safety precautions and manufacturer's information
Group 17 (VII) (halogens)
