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nikklg [1K]
3 years ago
6

What is the main difference between a longitudinal wave and a transverse wave? a longitudinal wave travels faster than a transve

rse wave. a transverse wave always has a larger amplitude than a longitudinal wave. the motion of the medium is parallel to a longitudinal wave and perpendicular to a transverse wave. the frequency is directly proportional to wavelength in a longitudinal wave but inversely proportional in a transverse wave.?
Physics
2 answers:
mote1985 [20]3 years ago
9 0
<span>The motion of the medium is parallel to a longitudinal wave
and perpendicular to a transverse wave.</span>
o-na [289]3 years ago
8 0

<u>Answer:</u> The correct answer is the motion of the medium is parallel to a longitudinal wave and perpendicular to a transverse wave.

<u>Explanation:</u>

There are two main types of waves:

1. Transverse Waves: These waves are the waves where the particles in a medium travel perpendicular to the direction of the wave. These waves do not require a medium to travel and can travel in vacuum also. For Example: Light waves.

2. Longitudinal waves: These waves are the waves where the particles of the medium travel parallel to the direction of the wave and these waves require a medium to travel and hence, cannot travel in vacuum. For Example: Sound waves.

From the given options, the correct answer is  the motion of the medium is parallel to a longitudinal wave and perpendicular to a transverse wave.

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7. A toy car of mass 1.2 kg is driving vertical circles inside a hollow cylinder of radius 2.0m. It is moving at a constant spee
wlad13 [49]

Answer:

a)

N_{top}=9.8N\\N_{bottom}=33.4N

b) v_{min}=4.4m/s

Explanation:

The net force on the car must produce the centripetal acceleration necessary to make this circle, which is a_{cp}=\frac{v^2}{R}. At the top of the circle, the normal force and the weight point downwards (like the centripetal force should), while at the bottom the normal force points upwards (like the centripetal force should) and the weight downwards, so we have (taking the upwards direction as positive):

-m\frac{v^2}{R}=-N_{top}-mg\\m\frac{v^2}{R}=N_{bottom}-mg

Which means:

N_{top}=m\frac{v^2}{R}-mg=(1.2kg)\frac{(6m/s)^2}{2m}-(1.2kg)(9.8m/s^2)=9.8N\\N_{bottom}=m\frac{v^2}{R}+mg=(1.2kg)\frac{(6m/s)^2}{2m}+(1.2kg)(9.8m/s^2)=33.4N

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