Answer:
f = 614.28 Hz
Explanation:
Given that, the length of the air column in the test tube is 14.0 cm. It can be assumed that the speed of sound in air is 344 m/s. The test tube is a kind of tube which has a closed end. The frequency in of standing wave in a closed end tube is given by :
f = 614.28 Hz
So, the frequency of the this standing wave is 614.28 Hz. Hence, this is the required solution.
Answer:
the resistance of the second wire is 1 ohm.
Explanation:
Given;
cross sectional area of the first wire, A₁ = 5.00 x 10⁶ m²
resistance of the first wire, R₁ = 1.75 ohms
cross sectional area of the second wire, A₂ = 8.75 x 10⁶ m²
resistance of the second wire, R₂ = ?
The resistance of a wire is given as;
R ∝
Since the length of the two wires is constant
R₁A₁ = R₂A₂
Therefore, the resistance of the second wire is 1 ohm.
Answer:
<em>If it served you, give me 5 stars please, thank you! </em>
<u>Muzzle velocity 300 m/s</u> corresponds to the .38 special
Thus, the shooter is Janice Jackson with .38 special.
