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Snowcat [4.5K]
3 years ago
5

When we go up From the earth surface.what happens about the atmospheric pressure​

Physics
1 answer:
topjm [15]3 years ago
7 0

Answer:

There are two reasons why air pressure decreases as altitude increases: density and depth of the atmosphere. Most gas molecules in the atmosphere are pulled close to Earth's surface by gravity, so gas particles are denser near the surface.

Explanation:

You might be interested in
Calculate the electric potential energy in a capacitor that stores 4.0 x 10-10 C
ioda

The electric potential energy is 1\cdot 10^{-7} J

Explanation:

The electric potential energy stored in a capacitor is given by the equation

PE=Q \Delta V

where

Q is the charge stored in the capacitor

\Delta V is the potential difference between the plates

For the capacitor in this problem, we have

Q=4.0\cdot 10^{-10}C is the charge

\Delta V=250.0 V is the potential difference

Substituting, we find the potential energy:

PE=(4.0\cdot 10^{-10})(250.0)=1\cdot 10^{-7} J

Learn more about capacitors:

brainly.com/question/10427437

brainly.com/question/8892837

brainly.com/question/9617400

#LearnwithBrainly

4 0
3 years ago
Read 2 more answers
Given 4.8 moles of a gas at 37 degrees Celsius and at 792 torr, what is the volume of the gas? (The ideal gas constant is 0.0821
Anastaziya [24]

Answer:

1.17 x 10^2 L

Explanation:

We can find the volume of the gas by using the ideal gas law:

pV=nRT

where we have:

p=792 Torr \cdot \frac{1 atm}{760 Torr} = 1.04 atm is the pressure

V is the volume

n = 4.8 mol is the number of moles

R = 0.0821 L · atm/mol · K is the ideal gas constant

T=37^{\circ}+273 =310 K is the temperature

Solving the equation for V, we find the volume

V=\frac{nRT}{p}=\frac{(4.8 mol)(0.0821 L atm/mol K)(310 K)}{1.04 atm}=117.5 L = 1.17\cdot 10^2 L

4 0
3 years ago
A 65.0-kg woman steps off a 11.0-m diving platform and drops straight down into the water. 1) If she reaches a depth of 4.60 m,
Ganezh [65]

Answer:

2160.26 N.

Explanation:

From the question,

The total energy of the woman = work done by the water.

mg(h+d) = F'×d.......................... Equation 1

m = mass of the the woman, g= acceleration due to gravity, h = height of the platform, d = depth of water reached by the woman, F'= Resistance force exerted on her by the water.

make F' the subject of the equation

F' = mg(h+d)/d............................ Equation 2

Given: m = 65.0 kg, g = 9.8 m/s², h = 11 m, d = 4.6 m.

Substitute into equation 2

F' = 65(9.8)(11+4.6)/4.6

F' = 9937.2/4.6

F' = 2160.26 N.

8 0
3 years ago
I Need help please with this question..
pantera1 [17]
D............................
4 0
3 years ago
How do you answer this. Need help ASAP. Offering 20 points !!!
Temka [501]

in this since your volume remains at a constant you'll need to use Gay-Lussacs law, p1/t1=p2/t2.

your temp should be converted in kelvin

variables:

p1=3.0×10^6 n/m^2

t1= 270k

just add 273 to your celcius

p2= ? your solving for this

t2= 315k

then you set up the equation

(3.0×10^6)/270= (x)(315)

you then cross multiply

(3.0×10^6)315=270x

distribute the 315 to the pressure.

9.45×10^8=270x then you divide 270 o both sides to get

answer

3.5×10^6 n/m^2

7 0
3 years ago
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