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deff fn [24]
3 years ago
9

What temperature can a solar flare reach

Physics
1 answer:
balandron [24]3 years ago
5 0
It reaches 10 or 20 million degrees kelvin but it can get as high as 10 million degrees kelvin
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The energy band gap of GaAs is 1.4 eV. Calculate the optimum wavelength of light for
notsponge [240]

Answer:

The optimum wavelength = (8.863 × 10⁻⁷) m = 886.3 nm

Explanation:

The light that will generate the photovoltaic energy of 1.4 eV will must have that amount of energy

Energy of light waves is given as

E = hf

h = Planck's constant = (6.626 × 10⁻³⁴) J.s

f = Frequency of the light

The frequency is then further given as

f = (c/λ)

c = speed of light = (3.0 × 10⁸) m/s

λ = wavelength of the light = ?

E = (hc/λ)

λ = (hc/E)

Energy = E = 1.4 eV = 1.4 × 1.602 × 10⁻¹⁹ = (2.2428 × 10⁻¹⁹) J

λ = (6.626 × 10⁻³⁴ × 3.0 × 10⁸)/(2.2428 × 10⁻¹⁹)

λ = (8.863 × 10⁻⁷) m = 886 nm

Hope this Helps!!!

3 0
3 years ago
Calculate the mass 9f the earth, assuring that uts is sphere with radius 6.67×10^6m.​
MA_775_DIABLO [31]

Answer:

6.86 × 10²⁴ kg

Explanation:

The mass of the earth m = density of earth, ρ × volume of earth, V

m = ρV

The density of the earth, ρ = 5515 kg/m³ and since the earth is a sphere, its volume is the volume of a sphere V = 4πr³/3 where r = radius of the earth = 6.67 × 10⁶ m

Since m = ρV

m = ρ4πr³/3

So, substituting the values of the variables into the equation for the mass of the earth, m, we have

m = 5515 kg/m³ × 4π(6.67 × 10⁶ m)³/3

m = 5515 kg/m³ × 4π × 296.741 × 10¹⁸ m³/3

m = 5515 kg/m³ × 1189.9639π × 10¹⁸ m³/3

m = 6546105.64378π × 10¹⁸ kg/3

m = 20565197.400122 × 10¹⁸ kg/3

m = 6855065.8 × 10¹⁸ kg

m = 6.8550658 × 10²⁴ kg

m ≅ 6.86 × 10²⁴ kg

8 0
3 years ago
The psychologist known for latent learning and cognitive maps is _________. A. Robert Rescorla B. Edward Tolman C. William James
Lubov Fominskaja [6]

Answer:

B

Explanation:

B. Edward Tolman

4 0
3 years ago
Read 2 more answers
1. Determine the magnitude of two equal but opposite charges if they attract one another with a force of 0.7N when at distance o
adell [148]

Answer:

q = 2.65 10⁻⁶ C

Explanation:

For this exercise we use Coulomb's law

        F =k \frac{q_1q_2}{r^2}

In this case they indicate that the load is of equal magnitude

       q₁ = q₂ = q

the force is attractive because the signs of the charges are opposite

       F = k \ \frac{q^2}{r^2}

       q = \sqrt{\frac{F \ r^2}{k} }

we calculate

        q = \sqrt{\frac{0.7 \ 0.3^2 }{9 \ 10^9}  }

        q = \sqrt{7 \ 10^{-12} }Ra 7 10-12

        q = 2.65 10⁻⁶ C

7 0
3 years ago
What is the mass of a basketball that has Connecticut energy of 102 J and it's travelling at 5 m/s
Stella [2.4K]

Answer:

8.16Kg

Explanation:

K.E= 1/2 mv²

102=1/2 m 5²

m=8.16 Kg

8 0
3 years ago
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