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2 years ago

How does inertia affect a person who is not wearing a seatbelt during a collision?

Physics

2 answers:

ELEN [110]2 years ago

7 0

A person who is not wearing a seatbelt during a collision will be thrown forward because it maintains forward motion

<h3>Further explanation </h3>

In Newton's law, it is stated that if the resultant force acting on an object of magnitude is zero, it can be formulated :

$\large{\boxed{\bold{\Sigma F = 0}}}$

then the object tends to defend itself from its state. So for objects in a state of movement, objects tend to move forever. Likewise, for objects in a state of rest, they tend to remain forever. The tendency of objects like this is called<em> inertia </em>

The size of inertia is proportional to mass, the greater the mass of the object, the greater the inertia of the object.

In objects with mass m that move translatively, the object will maintain its linear velocity

When we are in a vehicle that moves forward, then we will still maintain a state of forwarding motion. If our vehicle stops suddenly, then we keep moving forward so we will be pushed forward. From this point, the use of a safety belt serves to hold back our movements so that there are no fatal accidents or collisions.

<h3>Learn more </h3>

Newton's law of inertia

brainly.com/question/1412777

example of Newton's First Law of inertia

brainly.com/question/1090504

law of motion

brainly.com/question/75210

Keywords: inertia, Newton's First Law

kari74 [83]2 years ago

3 0

<u><em>The person not wearing the seat-belt during a collision may hit the dashboard of the car very hard and this injury might be fatal.</em></u>

Explanation:

The inertia of a body is a property contained by the body by virtue of its mass. Higher the mass of a body, higher will be the inertia.

According to the Newton's first law of motion i.e. law of Inertia, a body continues to be in its state of rest or motion until and unless an external force acts on the body to change its state.

When a car is moving on a road, the car is in motion and the body of the person in the car is also in the motion along with the car. Now if the car faces any collision, the car will suddenly come to rest.

But the body of the person sitting in the car continues to be in motion as there is no external force acting on the body. If the person is not wearing the seat-belt, the body moves forward and the person may hit the dashboard very hard.

The seat-belt stops the person's body to move ahead and hit the dashboard. So, the seat-belt prevents the person from injury by stopping the body.

Thus, <u><em>The person not wearing the seat-belt during a collision may hit the dashboard of the car very hard and this injury might be fatal.</em></u>

Learn More:

1. The component of a lever brainly.com/question/1073452

2. The kinetic energy of a body depends on brainly.com/question/137098

3. How long to walk 2000 miles brainly.com/question/3785992

Answer Details:

Grade: High School

Subject: Physics

Chapter: Laws of Motion

Keywords:

inertia, law of motion, newton's law, seat-belt, collision, wearing, dashboard, injury, external force, rest, motion.

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3 years ago

In which medium does light travel faster: one with a critical angle of 27.0° or one with a critical angle of 32.0°? Explain. (Fo

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Answer:

Among those two medium, light would travel faster in the one with a reflection angle of $32^{\circ}$ (when light enters from the air.)

Explanation:

Let $v_{1}$ denote the speed of light in the first medium. Let $v_{\text{air}}$ denote the speed of light in the air. Assume that the light entered the boundary at an angle of $\theta_{1}$ to the normal and exited with an angle of $\theta_{\text{air}}$ . By Snell's Law, the sine of $\theta_{1}\!$ and $\theta_{\text{air}}\!$ would be proportional to the speed of light in the corresponding medium. In other words:

$\displaystyle \frac{v_{1}}{v_{\text{air}}} = \frac{\sin(\theta_{1})}{\sin(\theta_{\text{air}})}$ .

When light enters a boundary at the critical angle $\theta_{c}$ , total internal reflection would happen. It would appear as if the angle of refraction is now $90^{\circ}$ . (in this case, $\theta_{\text{air}} = 90^{\circ}$ .)

Substitute this value into the Snell's Law equation:

$\begin{aligned}\frac{v_{1}}{v_{\text{air}}} &= \frac{\sin(\theta_{1})}{\sin(\theta_{\text{air}})} \\ &= \frac{\sin(\theta_{c})}{\sin(90^{\circ})} \\ &= \sin(\theta_{c})\end{aligned}$ .

Rearrange to obtain an expression for the speed of light in the first medium:

$v_{1} = v_{\text{air}} \cdot \sin(\theta_{1})$ .

The speed of light in a medium (with the speed of light slower than that in the air) would be proportional to the critical angle at the boundary between this medium and the air.

For $0 < \theta < 90^{\circ}$ , $\sin(\theta)$ is monotonically increasing with respect to $\theta$ . In other words, for $\!\theta$ in that range, the value of $\sin(\theta)\!$ increases as the value of $\theta\!$ increases.

Therefore, compared to the medium in this question with $\theta_{c} = 27^{\circ}$ , the medium with the larger critical angle $\theta_{c} = 32^{\circ}$ would have a larger $\sin(\theta_{c})$ . such that light would travel faster in that medium.