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eimsori [14]
4 years ago
11

What volume is occupied by 5.80×10^20 molecules of an ideal gas at STP?

Chemistry
1 answer:
Neko [114]4 years ago
3 0

Answer:

<u></u>

  • <u>0.0219 liter</u>

Explanation:

The current temperature and pressure at <em>STP </em>(Standard Temperature and Pressure) stated by IUPAC are:

  • Temperature: 273.15 K (0 °C)

  • Pressure: 10⁵ Pa ≈ 0.9869 atm

Using the <em>ideal gas </em>equation, pV = nRT,  and the Avogadro constant, you can find the<em> volume occupied by 5.80 × 10²⁰ molecules.</em>

           pV=nRT\\\\  \\ V=\dfrac{nRT}{p}

V=\dfrac{5.80\cdot 10^{20}molec\times \dfrac{1mol}{6.022\cdot 10^{23}molec}\times 0.08206\dfrac{atm.liter}{mol.K}\times 273.15K}{0.9869atm}

          V=2.19e^{-2}liter=0.0219liter

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3 years ago
If 9.85 grams of copper metal react with 31.0 grams of silver nitrate, how many grams of copper nitrate can be formed and how ma
Veseljchak [2.6K]

Answer:-

29.07 gram of Cu(NO3)2 will be formed.

4.756 grams of AgNO3 will be left over when the reaction is complete.

Explanation:-

Atomic weight of Cu = 63.546 g mol -1

Molecular weight of AgNO3 = 107.87 x 1 + 14 x 1 + 16 x 3

= 169.87 g mol-1

Number of moles of Copper = 9.85 gram / (63.546 g mol-1)

= 0.155 mol

Number of moles of AgNO3 = 31 gram / ( 169.87 g mol-1)

= 0.183 mol

The balanced chemical equation for this reaction is

Cu + AgNO3 --> Cu(NO3)2 + Ag

According to the equation,

1 mole of Cu reacts with 1 mole of AgNO3.

∴0.155 mol of Cu react with 0.155 mol of AgNO3.

Number of moles of AgNO3 left over = 0.183-0.155=0.028 mol

Number of grams of AgNO3 left over = 0.028 mol x 169.87 grams mol-1

= 4.756 gram

Molecular weight of Cu(NO3)2 = 63.546 x 1 + (14 x 1 +16 x 3 ) x 2

=187.546 gram

Now from the balanced chemical equation,

1 Cu gives 1 Cu(NO3)2

∴ 63.546 g of Cu gives 187.546 gram of Cu(NO3)2

9.85 grams pf Cu gives 187.546 x 9.85 / 64.546 gram of Cu(NO3)2

= 29.07 gram of Cu(NO3)2

4 0
3 years ago
What is the mass of 8.90 moles of magnesium chloride, MgCl2?
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3 years ago
Using the equation 2H2+O2=2H2O, when 47g of water are produced, how many grams of hydrogen must react?
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See , from the equation we can see that for forming two mole of H2O 2Mole of H2 has to react.

Mass of 2 Mole H2O is 18*2gm or 36gm.

So for forming 36 gm H2O 2×2 I.e. 4 gm H2 has to take part in reaction.

Therefore, to form 1 gm H2O 4÷36 gm of H2 has to take part.

So, for forming 47gm H2O (4÷36)×47 gm H2 has to take part

I.e. 5.22 gm of H2 has to take part

So, ans is 5.22 gm of hydrogen.

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6 0
3 years ago
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There are 1.204 x 10^24 atoms of oxygen. How many moles is this?
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Answer:

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Explanation:

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