What mass of carbon monoxide is needed to react with 1000g of iron oxide?

Chemistry

1 answer:

maw [93]2 years ago

4 0

Answer:

The equation for one of the reactions in the process of turning iron ore into themetal isFe2O3(s) + 3 CO(g) -> 2 Fe(s) + 3 CO2(g)If you start with 2.00 kg of each reactant, what i…

Explanation:

The equation for one of the reactions in the process of turning iron ore into the metal isFe2O3(s) + 3 CO(g) -> 2 Fe(s) + 3 CO2(g)If you start with 2.00 kg of each reactant, what i…

You might be interested in

Which form of oxygen (solid,liquid or gas) would have the highest temperature

ElenaW [278]

Answer:

drip drip water splash (gas)

Explanation:

8 0

3 years ago

Is a stick of dynamite potential energetic or kinetic

qwelly [4]

Answer:Potential Energy

Explanation:

It is because a stick dynamite is a stored energy which have to be acted upon(lighting it) for it to explode

3 0

3 years ago

Read 2 more answers

Which vein carries oxygenated blood back into the heart?

Finger [1]

Answer:

The veins that carry oxygenated bloof back into the heart are the pulmonary arteries.

Explanation:

Oxygen-rich blood flows from the lungs back into the left atrium (LA), or the left upper chamber of the heart, through four pulmonary veins. Oxygen-rich blood then flows through the mitral valve (MV) into the left ventricle (LV), or the left lower chamber.

6 0

2 years ago

Read 2 more answers

A sample of nitrogen gas has the temperature drop from 250.°c to 150.°c at constant pressure. what is the final volume if the in

Leviafan [203]

Charles law gives the relationship between temperature of gas and volume of gas.
It states that for a fixed amount of gas, temperature is directly proportional to volume of gas.
V / T = k
where V- volume , T - temperature and k - constant
$\frac{V1}{T1} = \frac{V2}{T2}$
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation.
T1 = 250 °C + 273 = 523 K
T2 = 150 °C + 273 = 423 K
Substituting the values in the equation,

$\frac{310 mL}{523 K} = \frac{V}{423K}$
V = 251 mL
the new volume is 251 mL

6 0

3 years ago

What is the pH of pure water at 40.0Â°C if the Kw at this temperature is 2.92 - 10-147 OA) 6.767 O B) 0 465 O c) 7.000 OD) 7 233

Sergeeva-Olga [200]

Answer:

PH= 6.767 (answer is the A option)

Explanation:

first we need to correct the value in Kw at this temperature is 2.92*10^-14

so, in this case we have that:

Kw=2.92*10^-14 M²

[ H3O^+] [ H3O^+]

$[H_{3}O^{+} ] [OH^{-} ] = Kw = 2.92*10^{-14} M^{2} \\\\$