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2 years ago

What mass of carbon monoxide is needed to react with 1000g of iron oxide?

Chemistry

1 answer:

maw [93]2 years ago

4 0

Answer:

The equation for one of the reactions in the process of turning iron ore into themetal isFe2O3(s) + 3 CO(g) -> 2 Fe(s) + 3 CO2(g)If you start with 2.00 kg of each reactant, what i…

Explanation:

The equation for one of the reactions in the process of turning iron ore into the metal isFe2O3(s) + 3 CO(g) -> 2 Fe(s) + 3 CO2(g)If you start with 2.00 kg of each reactant, what i…

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Methyl salicylate is a common active ingredient in liniments such as ben-gay. It is also known as oil of wintergreen. It is made

arlik [135]

Answer: The empirical formula is $C_3H_3O$ .

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2$ = 12.24 g

Mass of $H_2O$ = 2.505 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 12.24 g of carbon dioxide, = $\frac{12}{44}\times 12.24=3.338g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 2.505 g of water, = $\frac{2}{18}\times 2.505=0.278g$ of hydrogen will be contained.

Mass of oxygen in the compound = (5.287) - (3.338+0.278) = 1.671 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{3.338g}{12g/mole}=0.278moles$

Moles of H= $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.278g}{1g/mole}=0.278moles$

Moles of O= $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{1.671g}{16g/mole}=0.104moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{0.278}{0.104}=3$

For H = $\frac{0.278}{0.104}=3$

For O = $\frac{0.104}{0.104}=1$

The ratio of C : H : O = 3: 3: 1

Hence the empirical formula is $C_3H_3O$ .

5 0

3 years ago

Explain why the boiling point of H2S with relative molecular mass 34 is lower than that of H2O with relative molecular mass 18

Levart [38]

Answer and Explanation:

In H2O molecules, due to formation of intermolecular hydrogen bonds, there is molecular association. Large amount of energy is required to break these intermolecular hydrogen bonds. Intermolecular hydrogen bonding is not possible in H2S. Hence, its boiling point is lower and is a gas.

4 0

3 years ago

LEWIS DOT<br> Mg3 N2 how do I get my answer

Mashutka [201]

Answer:

mayori moriti

Explanation:

dot al time

5 0

3 years ago

What is the molarity of a solution where there are 1.35 moles of H2SO4 in 3.00 L of solution?

Montano1993 [528]

Answer: 0.450 M H2SO4

Explanation:

To solve this problem, we must remember how to compute molarity. To find the molarity of a solution, we divide the number of moles by the number of liters of solution. Using this formula and substituting the given values, we get:

Molarity = moles solute/liters solution

= 1.35 moles/3.00 L

= 0.450 M H2SO4

Therefore, the correct answer is 0.450 M H2SO4. Note that the answer has 3 significant figures because each of the given values also contains 3 significant figures.

Hope this helps!

4 0

2 years ago

A mass of 14 kg is accelerated at 2m/s2 for a distance of 5 meters. How much energy is required?

soldi70 [24.7K]

Force = mass * acceleration

= 14 * 2 = 28N

Work done (energy) = Force * distance

= 28 * 5 = 140J

3 0

3 years ago