Ribosomes hope this helps if not oh well
Answer:
The total mass of D-Glucose dissolved in a 2μL aliquot is 1 E-4 g
Explanation:
providing a solution to 5% weight-volume as found in commerce:
⇒ % 5 = (5g d-glucose/ 100 mL sln)×100
⇒ 0.05 = g C6H12O6/mL sln
⇒ g C6H12O6 = (2 μL sln)×(0.001 mL/μL)×(0.05 g C6H12O6/mL sln)
⇒ g C6H12O6 = 1 E-4 g C6H12O6
Answer:
the answer is a
Explanation:
i did process of elimination and i got a
Answer:
The answer to your question is 3% H2SO4 solution
Explanation:
Data
Concentration 2 = C₂ = ?
Concentration 1 = C₁ = 15 %
Volume 1 = V₁ = 50 ml
Volume 2 = V₂ = 250 ml
Formula
C₁V₁ = C₂V₂
Solve for C₂
C₂ = C₁V₁ / V₂
Substitution
C₂ = (15)(50) / 250
Simplification and result
C₂ = 3 %
A) mass / volume = density
m/6.00cm3 = 13.5939g/cm3
m = 13.5939g/cm3 • 6.00cm3
m = 81.6g
B) mass / volume = density
m/25.0cm3 = 0.702g/cm3
m = 0.702cm3 • 25.0g/cm3
m = 17.6g
1mL = 1cm3
