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Yanka [14]
3 years ago
10

A star has a size of 0.1 solar radius. How many times larger is the sun than this star?

Chemistry
1 answer:
solniwko [45]3 years ago
6 0
The sun is 10x larger than this star.
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Metamorphism can best be defined as
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How would you find the volume of a regular object and irregular object?
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If you have 3cm of each<br> substance, which would<br> have the MOST MASS
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5 0
3 years ago
Calculate the concentration of chloride ions when 100.0 mL of 0.233 M sodium chloride is mixed with 250.0 mL of 0.150 M calcium
serg [7]
The dissociation of both salts NaCl and CaCl₂ are as follows;
NaCl --> Na⁺ + Cl⁻

CaCl₂ --> Ca²⁺ + 2Cl⁻

the molar ratio of NaCl to Cl⁻ is 1:1
therefore number of NaCl moles is equal to number of Cl⁻ ions dissociated from NaCl
then number of Cl⁻ ion moles - 0.233 mol/L x 0.1000 L = 0.0233 mol

molar ratio of CaCl₂ to Cl⁻ ions is 1:2
1 mol of CaCl₂ gives out 2 mol of Cl⁻ ions.
number of CaCl₂ moles - 0.150 mol/L x 0.2500 L  = 0.0375 mol 
then the number of Cl⁻ ion moles - 0.0375 x 2 = 0.0750 

total number of Cl⁻ ion moles = 0.0233 mol + 0.0750 mol = 0.0983 mol
volume of solution - 100.0 + 250.0 = 350.0 mL 

concentration of Cl⁻ = 0.0983 mol / 0.3500 L = 0.281 M
concentration of Cl⁻⁻ is 0.281 M 
4 0
3 years ago
A sample of an unknown gas takes 371 s to diffuse through a porous plug at a given temperature.
blsea [12.9K]

Answer:

125.84 g/mol is the molar mass of the unknown gas.

Explanation:

Let the volume of the gases effusing out be V.

Effusion rate of the unknown gas = R=\frac{V}{371 s}

Effusion rate of the nitrogen gas = r=\frac{V}{175 s}

Molar mass of unknown gas = m

Mass of nitrogen gas = 28 g/mol

Graham's law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

\frac{R}{r}=\sqrt{\frac{28 g/mol}{M}}

\frac{\frac{V}{371 s}}{\frac{V}{175s}}=\sqrt{\frac{28 g/mol}{M}}

\frac{175 s}{371 s}=\sqrt{\frac{28 g/mol}{M}}

M=\frac{28 g/mol\times 371\times 371}{175\times 175}=125.84 g/mol

125.84 g/mol is the molar mass of the unknown gas.

5 0
3 years ago
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